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2.57 joule energy lose in the bounce
.
<u>Explanation</u>:
when ball is the height of 1.37 m from the ground it has some gravitational potential energy with respect to hits the ground
Formula for gravitational potential energy given by
Potential Energy = mgh
Where
,
m = mass
g = acceleration due to gravity
h = height
Potential energy when ball hits the ground
m= 0.375 kg
h = 1.37 m
g = 9.8 m/s²

Potential Energy = 5.03 joule
Potential energy when ball bounces up again
h= 0.67 m

Potential Energy = 2.46 joule
Energy loss = 5.03 - 2.46 = 2.57 joule
2.57 joule energy lose in the bounce
The distance covered will be 0.301m.
firstly we will new to calculate acceleration (a).
we can do so using newtons first law of motion.
v=u + a × t
where
a is the acceleration
t is the time
from here we get
a=(v-u)/t
a=(4-0)/0.15
a=26.67m/s²
using newtons second law of motion
s=u.t+1/2at²
where s is distance travelled in t seconds.
we get,
s=0.301m
learn more about newtons law of motion here:
brainly.com/question/129361
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