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Nostrana [21]
3 years ago
7

When positively charged particles were radiated onto a gold atom, most of the particles went straight past. What is most likely

the reason for this? Dense area inside the atom. B. Empty space around the nucleus. C. Scattered positively charged particles in the atom. D. Electrons and neutrons inside the nucleus
Chemistry
2 answers:
MissTica3 years ago
7 0

Answer: Option (B) is the correct answer.

Explanation:

In Rutherford's gold foil experiment, the positively charged particles which were radiated onto a gold atom were alpha particles.

It is known that nucleus of an atom has protons and neutrons. When a beam of positively charged particles is passed through the nucleus then some of the alpha particles colloid with the protons and neutrons. Hence, they get deflected back.

Whereas some alpha particles pass through the empty space around the nucleus as a result, they pass straight past and does not get deflected.

Thus, we can conclude that when positively charged particles were radiated onto a gold atom, most of the particles went straight past due to empty space around the nucleus.


Snowcat [4.5K]3 years ago
6 0
<span> "B. Empty space around the nucleus"
because of this empty space, most radiated particles can pass </span>straight through, while the others get propelled in different directions.
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Select all the signs of a CHEMICAL change from the list below. (You may need to select more than one for full points)
wlad13 [49]

The answers are B, C, and D.

4 0
4 years ago
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What is the freezing point of a solution of 498mL of water (solute) dissolved in 2.50 L of ethanol (solvent), C2H5OH? The densit
jok3333 [9.3K]

Answer:

Freezing T° of solution is -142.4°C

Explanation:

This excersise is about colligative properties, in this case freezing point depression,

ΔT = Kf . m . i

Where ΔT = Freezing T° of solvent - Freezing T° of solution

Kf = Cryoscopic constant

m = mol/kg (molality)

i = Number of ions dissolved.

Water is not ionic, so i = 1

Let's find out m.

We determine mass of water, by density

498ml . 1 g/mL = 498 g

We convert the mass of water to moles → 498 g . 1mol/18g = 27.6 moles

We determine mass of solvent by density

2500 mL . 0.789 g/mL = 1972.5 g

Notice, we had to convert L to mL to cancel units.

1 cm³ = 1 mL

We convert the mass from g to kg → 1972.5 g . 1kg /1000g = 1.97kg

We determine m = mol/kg → 27.6mol / 1.97kg = 13.9 m

Kf for ethanol is: 1.99 °C/m

Freezing T° for ethanol is: -114.6°C

We replace at formula: - 114.6°C - Freezing T° solution = 1.99 °C/m . 13.9 m . 1

- 114.6°C - Freezing T° solution = 27.8 °C

- Freezing T° solution  = 27.8°C + 114.6°C

Freezing T° Solution = - 142.4 °C

7 0
3 years ago
1.50μm2. Convert this to square meters.
Verizon [17]
1.50x10^6 m2 is the answer you're looking for 
6 0
3 years ago
use dimensional analysis to determine how many atoms of o2 produced in a reaction that yields 2 mol of o2
Alex73 [517]

The number of atoms of oxygen is 2.4 * 10^24.

<h3>How many atoms are produced?</h3>

We know that mole of a substance contains the Avogadro's number of atoms. The Avogadro's number gives the number of atoms, molecules, ions and atoms that could be found in one mole of a substance.

Now;

Given that ;

1 mole of oxygen contains two atoms of oxygen, the number of atoms that are contained in 2 moles of the oxygen molecule is;

2 * 2 * 6.023 * 10^23

= 2.4 * 10^24

Learn more about dimensional analysis:brainly.com/question/13078117

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8 0
1 year ago
(08.02
bogdanovich [222]

Answer:

b. The molarity of the solution increases

Explanation:

The correct answer is option b, that is the molarity of the solution increases.

Because the molarity is the concentration of the solution and it is explained as the amount of solute in amount of solution.

Solution: is the solute dissolved in solvent.

So if we increases the amount of solute in solvent the concentration in terms of molarity of solution increases and if we increase amount of solvent or water then the concentration or molarity increases.

Suppose we have form a sugar solution of 1 L by adding 4 mole of sugar then what happen

Use the Molarity formula

Molarity = no. of moles / 1 L of solution

put values in the formula

Molarity = 4/ 1 L of solution = 4 M

So the molarity of solution is 4 now if we add 2 mole more sugar to the same amount of sugar and amount of solution remain the same

now the no. of moles of sugar = 6 mole

So,

Use the Molarity formula

Molarity = no. of moles / 1 L of solution

put values in the formula

Molarity = 6 mol / 1 L of solution = 6 M

So the correct option is b.

7 0
3 years ago
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