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SSSSS [86.1K]
3 years ago
7

In a choir practice room, two parallel walls are 5.70 m apart. The singers stand against the north wall. The organist faces the

south wall, sitting 0.780 m away from it. To enable her to see the choir, a flat mirror 0.600 m wide is mounted on the south wall, straight in front of her. What width of the north wall can the organist see?
Physics
1 answer:
ololo11 [35]3 years ago
7 0

Answer:

4.98 m

Explanation:

Given that

Width of the mirror, d = 0.6 m

Organist distance to the mirror, s = 0.78 m

Distance between the singer and the organist, S = 5.7 + 0.78 = 6.48 m

Width of north wall, D?

Using the simple relationship

D/S = d/s, on rearranging

D = dS /s

D = (0.6 * 6.48) / 0.78

D = 3.888 / 0.78

D = 4.98 m

Therefore, we can conclude that the Width of north wall is 4.98 m

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Answer:

No, the ride is not safe

Explanation:

From the diagram attached, it is seen that

\sum f_{y} = 0

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\sum f_{x} = 0

-ma + \tau sin \theta = 0.......(2)

a = w^{2} r

From the diagram, r = Lsin \theta

a = w^{2} L sin \theta

w = \frac{2\pi }{T}

a = \frac{4\pi ^{2}L sin \theta }{T^{2} }............(3)

Put (3) into (2)

\tau sin \theta = \frac{4\pi ^{2}m L sin \theta }{T^{2} }

\tau  = \frac{4\pi ^{2}m L  }{T^{2} }

w = weight of chair + weight of child = 50 + 10 = 60 lb

g = 32 ft/s²

m = w/g = 60/32 = 1.875

L = 30 ft

T = 3 secs

\tau  = \frac{4\pi ^{2}*1.875*30  }{0.3^{2} }

\tau = 246.74 lbs

since 246.74 lbs > 200 lbs, it is not safe because the stationary chair will creak

6 0
3 years ago
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3 years ago
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Wittaler [7]

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Explanation:

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v(t) = 0  i  -  1  j   +3 t^2  k

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