If the object is in equilibrium that means that the sum of the forces on it is zero and the net force is zero. If none of the forces changes then the object continues in constant uniform motion. That means constant speed in a straight line.
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Answer:
Cp = 4756 [J/kg*°C]
Explanation:
In order to calculate the specific heat of water, we must use the equation of energy for heat or heat transfer equation.
Q = m*Cp*(T_f - T_i)/t
where:
Q = heat transfer = 2.6 [kW] = 2600[W]
m = mass of the water = 0.8 [kg]
Cp = specific heat of water [J/kg*°C]
T_f = final temperature of the water = 100 [°C]
T_i = initial temperature of the water = 18 [°C]
t = time = 120 [s]
Now clearing the Cp, we have:
Cp = Q*t/(m*(T_f - T_i))
Now replacing
Cp = (2600*120)/(0.8*(100-18))
Cp = 4756 [J/kg*°C]
Answer:
Explanation:
Given that,
Initial velocity, u = 44 m/s
Final velocity, v = 66 m/s
Time, t = 11 s
Acceleration = rate of change of velocity
So, the acceleration of the car is 
.
By applying the correspondent change of scale, we will see that Earth should be placed 214.8m away from the scale sun.
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How far the Earth should be placed?</h3>
The real radius of the Sun is:
R = 696,340 km
And the radius of the scale Sun is 1m, then we have the relation:
1m = 696,340 km
1 = (1m/696,340 km)
Now, the real distance between the Sun and Earth is:
d = 149,600,000 km
If we apply the change of scale we have above, we will get:
d = 149,600,000 km*(1m/696,340 km) = 214.8m
So the Earth should be placed at 214.8m of the ball that represents the sun.
If you want to learn more about changes of scale, you can read:
brainly.com/question/15891755
