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julia-pushkina [17]
3 years ago
15

Three identical satellites, X, Y, and Z are in outer space. The distance from satellite X to Y is 450 km, the distance from Y to

Z is 600 km, and the distance from satellite Z to X is 450 km. Between which satellites will the force of gravity be the greatest?
A. Between satellites Y and Z only.
B. Between satellites X and Y, and satellites Y and Z.
C. Between satellites Y and Z, and satellites X and Z.
D. Between satellites X and Y and satellites Z and X.
Physics
1 answer:
hodyreva [135]3 years ago
3 0
Gravity is stronger the closer you get. It is D.
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The answer is B. The nuclei of elements.
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A cylinder with moment of inertia I1 rotates with angular speed ω0 about a frictionless vertical axle. A second cylinder, with m
MAXImum [283]

Answer:

Part(a): The final angular velocity is \omega_{f} = \dfrac{I_{1}\omega_{i}}{(I_{1} + I_{2})}

Part(b): The ratio of the rotational energies is \dfrac{k_{f}}{k_{i}}& = \dfrac{I_{1}}{(I_{1} + I_{2})},showing the the energy of th system will decrease.

Explanation:

Part(a):

If 'I' be the moment of inertia of an object and '\omega' be its angular velocity then the angular momentum 'L' of the object can  be written as

L = I \omega

If 'I_{1}' and 'I_{2}' be the moment of inertia of the two cylinders and '\omega_{1}' and '\omega_{2}' be the initial angular velocity of the cylinders and '\omega_{1}{'}' and '\omega_{2}^'}' be their respective final angular velocity, then from conservation of angular momentum,

I_{1} \omega_{1} + I_{2} \omega_{2} = I_{1} \omega_{1}^{'} + I_{2} \omega_{2}^{'}

Given, \omega_{1} = \omega_{i},~\omega_{2} = 0,~\omega_{1}^{'} = \omega_{2}^{'} = \omega_{f}. From the above expression

&& I_{1} \omega_{i} = (I_{1} + I_{2}) \omega_{f}\\&or,& \omega_{f} = \dfrac{I_{1}\omega_{i}}{(I_{1} + I_{2})}

Part(b):

Initial kinetic energy  

K_{i} = \dfrac{1}{2} I_{1} \omega_{i}^{2}

and Final kinetic energy

K_{f} = \dfrac{1}{2}(I_{1} + I_{2}) \omega_{f}^{2}

Substituting the value of \omega_{f},

&& K_{f} = \dfrac{1}{2}(I_{1} + I_{2})\dfrac{I_{1}^{2}\omega_{i}^{2}}{(I_{1} + I_{2})^{2}} = \dfrac{1}{(I_{1} + I_{2})} \dfrac{1}{2}I_{1}\omega_{i}^{2} = \dfrac{1}{(I_{1} + I_{2})} K_{i}\\&\dfrac{k_{f}}{k_{i}}& = \dfrac{I_{1}}{(I_{1} + I_{2})}

The above expression shows that the ebergy of the system will decrease.

7 0
3 years ago
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scoundrel [369]

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A screw is a cylinder with a head (solid top) at one end and a pointed tip (like a nail) at the other end.

The mechanical advantage of the screw depends on the space between the threads and the length (and thickness) of the screw. The closer the threads are, the greater the mechanical advantage. It is easier to drive a screw into an object if the thread spacing is smaller.

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Changes in the forms of energy are called
Dima020 [189]
<span>Changes in the forms of energy are called "Energy Conversions"

Hope this helps!</span>
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