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larisa86 [58]
3 years ago
15

A 2.0-kg ball rolls to the right at 3.0 m/s. A 4.0-kg ball rolls to the left at 2.0 m/s . What is the momentum of the system aft

er a head-on collision of the two balls?
Physics
1 answer:
charle [14.2K]3 years ago
4 0

Answer:

Final momentum after a head on collision is -2kgm/s

Explanation:

         One ball moves to the right and the other moves opposite  and momentum is a vector quantity so that considering the direction

Initial momenta are        P₁=2x3=6kgm/s        P₂=4x(-2)=-8kgm/s      

Final momentum is the vector sum of P(final)= 6-8= -2 kgm/s

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Answer:

I have no clue

Explanation:

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2 years ago
hypnotist covers a distance of 5 kilometre in one hour and Rahul covers the same distance in 2 hour calculate the speed and stat
adell [148]

Answer:

At 5km/hr; Hypnotist travels with a higher speed.

Explanation:

Let hypnotist be H while Raul be R.

Given the following data;

Distance H = 5km

Time H = 1 hour

Distance R = 5km

Time R = 2 hours

To find the their respective speed;

a. For H;

Speed = distance/time

Speed H = 5/1

Speed H = 5km/hr

b. For R;

Speed = distance/time

Speed R = 5/2

Speed R = 2.5 km/hr

Therefore, hypnotist travels with a higher speed.

3 0
2 years ago
Which method of separation would you use when working in the garden and trying to separate the dirt from the weeds?
Thepotemich [5.8K]

Sifting is the best method cuz all the dirt will be carried by wind.

3 0
3 years ago
Read 2 more answers
A hiker begins a trip by first walking 25.0 km southeast from her car. She stops and sets up her tent for the night. On the seco
Sunny_sXe [5.5K]

Answer:

(a)

x_1=17.68km\\y_1=-17.68km\\x_2=20km\\y_2=34.64km

(b) r=41.32km

\alpha =24.23^o

Explanation:

Let us take the north direction to be the positive y-axis and the east to be positive x-axis.

First day:

25.0 km southeast, which implies 45^o south of east. The y-component will be negative and the x-component will be positive.

x_1=25cos45^o=17.68km

y_1=-25sin45^o=-17.68km

Second day:

She starts off at the stopping point of last day. This time, both the y- and x-components are positive.

x_2=40cos60^o=20km

y_2=40sin60^o=34.64km

Therefore, total displacements:

x=x_1+x_2=(17.68+20)km=37.68km

y=y_1+y_2=(-17.68+34.64)km=16.96km

Magnitude of displacements,

r=\sqrt{x^2+y^2}=41.32km

Direction,

\alpha =tan^{-1}(\frac{y}{x})=24.23^o

6 0
3 years ago
Two men standing on the same side of wall and at the same distance from It, such that they are 4oom apart when one fires a gun t
Mamont248 [21]

Answer:

1. 571.43m/s

2. 142.9m and 342.9m

Explanation:

1.Take the difference in time.

1.2-0.7=0.7 seconds

Take the distance between them and divide with differnce in time.

400÷0.7=571.43 seconds.

2.Take the time of the two men and divide by two.

0.5÷2= 0.25 secs

1.2÷2= 0.6 secs

multiply each with the velocity.

0.25×571.43=142.9m

0.6×571.43=342.9m

8 0
2 years ago
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