A 2.0-kg ball rolls to the right at 3.0 m/s. A 4.0-kg ball rolls to the left at 2.0 m/s . What is the momentum of the system aft
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Answer:
The location is at (3.535, 1.162) m
Solution:
As per the question:
Mass of the projectile, m = 9.6 kg
Initial velocity, v = 12.4 m/s
Angle,
Mass of one fragment, m = 6.5 kg
Time taken by the fragment, t = 1.42 s
Height of the fragment, y = 5.9 m
Horizontal distance, x = 13.6 m
Now,
To determine the location of the second fragment:
Horizontal Range,
Time of flight, t' =
Now, for the fragments:
Mass of the other fragment, m' = M - m = 9.6 - 6.5 = 3.1 kg
Distance traveled horizontally:
Distance traveled vertically:
Now,
x' = 3.535 m
Similarly,
The location of the other fragment is at (3.535, 1.162)