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fomenos
3 years ago
7

A gate at the bottom of a dam is 10 ft tall by 30 ft wide. The specific weight of the water is 62.4 lbf/ft3. If the water is 50

ft deep, the total force on the gate is most nearly:
Physics
1 answer:
Burka [1]3 years ago
4 0

Answer:

The total force is most nearly 940,000lbf

Explanation:

Total force = specific weight × volume

Volume = length × width × depth = 10ft × 30ft × 50ft = 15,000ft^3

Total force = 62.4lbf/ft^3 × 15,000ft^3 = 936,000lbf which is most nearly 940,000lbf

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Explanation:

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¿ cuales son las especies q mas características tienes en común ?
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What is the explanation for the fact that the desert sand is very hot in the day and very cool at night? 1. Sand reflects light
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5 0
2 years ago
Blake and Sandra are having a rummage sale. Blake drags 3 boxes a distance of 10 meters each. He exerts a force of 20 newtons on
vampirchik [111]
For Blake:

3 boxes at a distance of 10 meters each, each box weighs 20 N

Work done by Blake = 3 * 10m * 20N
                                 = 600 J
Power = 600 J/ 2 min
           = 300 J/min

For Sandra:

4 boxes, 15 N each at a distance of 12 meters each. 

Work done by Sandra = 4 * 15 N *12m
                                    =  720 J
Power = 720 J/ 4 min
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Blake does less work than Sandra. 
Blake's power is more than Sandra's.
5 0
3 years ago
Read 2 more answers
A powerful searchlight shines on a man. The man's cross-sectional area is 0.500m2 perpendicular to the light beam, and the inten
babymother [125]

Answer:

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N

(b) the force the light beam exerts is much too small to be felt by the man.

Explanation:

Given;

cross-sectional area of the man, A = 0.500m²

intensity of light, I = 35.5kW/m²

If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;

P = I/c

where;

P is the pressure of the incident light

I is the intensity of the incident light

c is the speed of light

P = \frac{I}{c} =\frac{35500}{3*10^8} = 1.18*10^{-4} \ N/m^2

F = PA

where;

F is the force of the incident light on the man

P is the pressure of the incident light on the man

A is the cross-sectional area of the man

F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N

Therefore, the force the light beam exerts is much too small to be felt by the man.

8 0
3 years ago
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