When testing to see how water affects plant growth, John make sure one set of his plants does not get water. This set of plants
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Answer:
(c) 0.11; (d) -24.5 kJ·mol⁻¹; (e) See below; (f) Kc increases;
(g) No effect on ΔH
Step-by-step explanation:
(c) Kc at 125 °C
In Part (a) one molecule of XY dissociated into one X and one Y.
XY ⇌ X + Y
I: 10 0 0
C: -1 +1 +1
E: 9 1 1
Kc = {[X][Y]}/[XY] = (1 × 1)/9 = ⅑ = 0.11
(d) ΔH
ΔH is a constant that is characteristic of the reaction.
ΔH = -24.5 kJ·mol⁻¹
(e) Effect of temperature on concentrations
If ΔH is negative, the reaction is exothermic.
Heat is a product of the reaction, so we can write the equation as
XY ⇌ X + Y + heat
If we lower the temperature, we are removing heat from the system.
<em>Le Châtelier's Principle</em> states that if you apply a stress to a system at equilibrium, it will respond by trying to relieve the stress.
We applied a stress by removing heat, so the system responds by producing more heat. The position of equilibrium moves to the right, and <em>more products will form</em>.
The diagram might look like the one below.
(f) Effect of temperature on Kc
Kc = [Products]/[Reactants]
We are increasing [Products] and decreasing [Reactants].
If you increase the numerator and decrease the denominator, you i<em>ncrease</em> the value of the quotient.
The value of the equilibrium constant increases when the temperature decreases.
(g) Effect of temperature on ΔH
Decreasing the temperature has no effect on ΔH, because the enthalpies of the reactants and products are properties of the substances themselves. They do not depend on the temperature.
<u>Answer:</u>
The temperature of the water is 70°C
<u>Explanation:</u>
Partial pressure of helium gas = 526 mmHg
Total pressure inside the jar= 760 mmHg
Suppose partial pressure of helium gas is and partial pressure of water is
And total pressure is
As we know
Hence
Putting the values
In bar,
= 0.312 bar
Now according to the steam table
With the vapour pressure of water as 0.312 bar the temperature corresponds to 70°C