From the question, the molarity of the desired solution was given as 0.235 M while the volume of the solution is 250 mL. Molarity is a unit of concentration used for solutions. It is necessary to first define what molarity is to be able to answer the question. Molarity is defined as number of moles of solute divided by the volume of the solution.
In this case, the amount of solid KCl required to obtain a concentration of 0.235 M in a volume of 250 mL is to be determined. The molar mass of KCl will also be used as conversion factor from unit of moles to grams. The value is 74.5513 g/mol. The following equation is used:
0.235 mol/ L x 1 L/1000 mL x 250 mL x 74.5513 g/mol KCl = 4.3799 g KCl
Thus, 4.38 g KCl is required to prepare 250 mL of 0.235 M solution.
First we need to find the number of moles of hydrogen gas formed
Zn + 2HCl ---> ZnCl₂ + H₂
stoichiometry of Zn to H₂ is 1:1
the number of Zn moles reacted - 2.4 g / 65.4 g/mol = 0.0367 mol
assuming Zn to be the limiting reactant
number of Zn moles reacted = number of H₂ moles formed
therefore number of H₂ moles formed = 0.0367 mol
we can use ideal gas law equation to find the pressure
PV = nRT
P - pressure
V - Volume - 450 x 10⁻⁶ m³
n - number of moles - 0.0367 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation
P x 450 x 10⁻⁶ m³ = 0.0367 mol x 8.314 Jmol⁻¹K⁻¹ x 305 K
P = 206.8 kPa
pressure is 206.8 kPa
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In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:
Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:
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