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vitfil [10]
3 years ago
8

A sailor pulls a crate across the deck of a ship with a rope, exerting a horizontal force of 150. N. The crate, which has a mass

of 50.0 kg, accelerates at 0.0600 m/s2.
a. List the forces acting on the crate. Assume the crate is moving slow enough for air resistance to be negligible.
b. What is the net force on the crate? Be sure to include a unit and the correct number of sig figs.
c. What is the magnitude of the friction force acting on the crate? Be sure to include a unit and the correct number of sig figs.
Physics
1 answer:
nata0808 [166]3 years ago
7 0

Answer:

B

Explanation:

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An electric dipole is formed from ±1.00nC charges spaced 3.00 mm apart. The dipole is at the origin, oriented along the x-axis.
Ronch [10]

Answer:

Value of electric field along the axis and equitorial axis  E=31.25\ N/c and E = 15.625\ N/c respectively.

Explanation:

Given :

Distance between charges , d = 3 \ mm =\dfrac{3}{1000}\ m=3\times 10^{-3}\ m.

Magnitude of charges , q=1\ nC = 10^{-9}\ C.

Dipole moment , p=qL=10^{-9}\times 3\times 10^{-3}=3\times 10^{-12} \ C\ m.

Case A) (x,y) = (12.0 cm, 0 cm) :

Electric field of dipole in its axis ,

E=\dfrac{2kp}{r^3}

Putting all values and r=12\times 10^{-2}\ m.

We get , E=31.25\ N/c.

Case B) (x,y) = (0 cm, 12.0 cm) :

Electric field of dipole on equitorial axis ,

E = \dfrac{kp}{r^3}

Putting all values and r=12\times 10^{-2}\ m.

We get , E = 15.625\ N/c.

Hence , this is the required solution.

7 0
3 years ago
Place the following into scientific notation...(.000635)<br> *
AleksAgata [21]
6.35x10^-4 OR 6.3x10-4 (if only one decimal number is allowed)
6 0
3 years ago
What current flows when a 35 v potential difference is imposed across a 1.4 kω resistor?
svetlana [45]

Current  =  (voltage) / (resistance)

              =    (35 volts) / (1,400 ohms)

              =         25 milliamperes 
5 0
3 years ago
When a flat slab of transparent material is placed under water, the critical angle for light traveling from the slab into water
Novosadov [1.4K]

Answer:

(a) 40.6 degree

Explanation:

When refraction takes place from slab to water, the critical angle is 60 degree.

Use Snell's law

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\mu _{w}^{s}=\frac{Sin60}{Sin90}

\frac{\mu _{w}}{\mu _{s}}=0.866

\frac{1.33}{\mu _{s}}=0.866

μs = 1.536

Now for slab air interface, the critical angle is C.

\mu _{a}^{s}=\frac{SinC}{Sin90}

\frac{\mu _{a}}{\mu _{s}}=\frac{SinC}{Sin90}

1 / 1.536 = Sin C

C = 40.6 degree

3 0
3 years ago
Lunar eclipse
vichka [17]

Answer:

Hey

Your answer would be

The moon is not visible

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The sun is not visible due

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The moon is on the side of

Earth opposite the sun=new moon

The moon and sun are on

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