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vitfil [10]
3 years ago
8

A sailor pulls a crate across the deck of a ship with a rope, exerting a horizontal force of 150. N. The crate, which has a mass

of 50.0 kg, accelerates at 0.0600 m/s2.
a. List the forces acting on the crate. Assume the crate is moving slow enough for air resistance to be negligible.
b. What is the net force on the crate? Be sure to include a unit and the correct number of sig figs.
c. What is the magnitude of the friction force acting on the crate? Be sure to include a unit and the correct number of sig figs.
Physics
1 answer:
nata0808 [166]3 years ago
7 0

Answer:

B

Explanation:

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natali 33 [55]

Answer:

Explanation:

Gravity is a field force since the earth does not have to actually “touch” an object to pull it toward the earth. A magnetic force is a field force that attracts or repels another magnet. Likewise, electric charges cause attracting or repelling forces without actual contact between the charges

8 0
2 years ago
A person pulls a box across the floor with a rope. The rope makes an angle of 40 degrees tot he horizontal, and a total of 125 n
RSB [31]

Answer:

The angle formed of the rope with the surface = 40°

Force applied = 125Newtons

The displacement covered by the box =25metres

W= FDcos theta

[125×40×cos(40°) ] Joules

= [ (3125×0.76604444311)]Joules

= 2393.88888472 joules(ans)

Hope it helps

3 0
2 years ago
Use wave equation calculate the speed of sound in the air if frequency of 110 hz has a wave length of 3 m
kirill115 [55]
Answer = 330 m/s

The wave equation is as follows:

Wave speed = wavelength x frequency

The known values are:
Wavelength = 3m
Frequency = 110 Hz

Substitute the known values into the wave equation to find the wave speed.

Wave speed = 3 x 110

Wave speed = 330 m/s
8 0
2 years ago
In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
Murljashka [212]

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

final speed of the box, v = 10 m/s

Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

¹/₂ x 8 x 10² = Ux

400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

8 0
3 years ago
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Peer review is important because it is used by scientists to decided which results should be published in a scientific journal
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3 years ago
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