Answer:
5.195 ml
Explanation:
Dissociation of HCl yields;
HCl(aq) ⇄ H⁺(aq) + Cl⁻(aq)
∴ [HCl] = [H⁺] = [Cl⁻]
pH = 1.9
= -log[ H⁺]
= 
= 
= 0.01258 M
Moles of HCl = number of mole × volume
= 0.01258 × 4.80 L
= 0.06042 mole
Mass of HCl = number of moles of HCl × Molar mass of HCl
Mass of HCl = 0.06042 mol × 36.5 g/mol
Mass of HCl = 2.205 grams
Also, given that the density = 1.179 g/mL
Mass of HCl in the solution = 36% of the density
i.e 
= 0.4244 grams
Volume of a concentrated HCl solution needed can now be determined as;
= 
= 
If Gold's natural state has a definite shape and a definite volume, then its natural state is solid.
B - The reactants are the starting substances and the products are the end substances.
Answer:
Atomic number of this isotope = 77
Explanation:
Given that,
Mass number = 193
No of neutrons = 116
We need to find the atomic no of this isotope.
We know that,
Atomic mass = No of protons + No. of neutrons
Also, atomic no = no of protons
So,
Atomic mass = atomic no + No. of neutrons
⇒ Atomic no = Atomic mass - no of neutrons
Atomic no = 193 - 116
Atomic no = 77
Hence, 77 is the atomic no of the isotope.
Answer:
It is true answer. Ozone = O3
