1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anon25 [30]
3 years ago
8

How can we specify / identify a certain electron? (Quantum forces)

Chemistry
1 answer:
Serga [27]3 years ago
3 0

Answer:

electrons are less than 1 amu, they are also negative charged. they are very small too

You might be interested in
How many moles are in 3.01 x 10^23 atoms of zinc?
Lerok [7]

Answer:

<h2>0.5 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.01 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{3.01}{6.02}  \\  = 0.5

We have the final answer as

<h3>0.5 moles</h3>

Hope this helps you

6 0
3 years ago
What is the percent yield of a reaction in which 51.5 g of tungsten(VI) oxide (WO3) reacts with excess hydrogen gas to produce m
Rus_ich [418]

Answer:

The percent yield of a reaction is 48.05%.

Explanation:

WO_3+3H_2\rightarrow W+3H_2O

Volume of water obtained from the reaction , V= 5.76 mL

Mass of water = m = Experimental yield of water

Density of water = d = 1.00 g/mL

M=d\times V = 1.00 g/mL\times 5.76 mL=5.76 g

Theoretical yield of water : T

Moles of tungsten(VI) oxide = \frac{51.5 g}{232 g/mol}=0.2220 mol

According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2220 moles of tungsten(VI) oxide will give:

\frac{3}{1}\times 0.2220 mol=0.6660 mol

Mass of 0.6660 moles of water:

0.666 mol × 18 g/mol = 11.988 g

Theoretical yield of water : T = 11.988 g

To calculate the percentage yield of reaction , we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{m}{T}\times 100=\frac{5.76 g}{11.988 g}\times 100=48.05\%

The percent yield of a reaction is 48.05%.

7 0
3 years ago
Read 2 more answers
MARKING BRAINLIEST
Evgesh-ka [11]

Answer:

I LIKE TRAINS

Explanation:

SNAILS ARE YUMMY

6 0
3 years ago
why can scientists ignore the forces of attraction between particles in a gas under ordinary conditions
Galina-37 [17]
The forces of attraction between particles in their gaseous state seems to be nonexistential.
therefore scientist would care less. however another state after gas which is plasma has a lesser force of attraction than the gaseous state.
8 0
3 years ago
11
Bess [88]

Answer:

Explanation:

<u>Manganese (VII) ion (an anion) has the formula MnO₄⁻</u>. A polyatomic ion is an ion that is made up of more than one atom. For example, MnO₄⁻ and NH₄⁺. Since the ion provided in the question is an anion, the polyatomic ion that would react with it will have to be a cation (positively charged).

<u>The polyatomic cation that will react with MnO₄⁻ to form a neutral compound is NH₄⁺ (ammonium ion) to form NH₄MnO₄ (Ammonium permanganate).</u>

6 0
3 years ago
Other questions:
  • Which of the following violates the Aufbau principle?
    12·1 answer
  • HCl + NaOH mc004-1.jpg NaCl + H2O Which substances are the reactants?
    7·1 answer
  • What temperature would be required to keep 0.895mol of gas in a 28.6L tank at a pressure of 0.500atm?
    6·1 answer
  • What is 6.24x10^-4 in regular numbers
    12·1 answer
  • 14. If ExGxP=Hx) solve for A<br> A<br> В
    8·1 answer
  • What pressure will be exerted by 0.57 moles of CO2 at a temperature of 25°C and a volume of 500 ML? _____atm
    15·1 answer
  • HELP NOW!!Why is it important to classify living organisms?
    12·1 answer
  • It took 10.40 mL of a NaOH solution to neutralize 0.307 g of KHP. What is the molarity of the NaOH solution
    9·1 answer
  • What is the concentration of a solution that is made by diluting 50.0 mL of a 0.40 M NaCl solution to a final volume of 1000.0 m
    10·1 answer
  • The maximum solubility of Ag2CO3 in 0.02<br>M Na2CO3 is (Ksp of<br>Ag2003 is 8 x 10-12)<br>​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!