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3 years ago

What are two equations for the energy of light? Identify each variable.

Physics

1 answer:

lorasvet [3.4K]3 years ago

3 0

Answer:

E = hv

E = hf

Explanation:

there are basically two equations for energy in light.

E = hf

where E is the energy of the photons. the unit is joules

h = the planck's constant . the unit is joules second

f = frequency of light. the unit is Hertz

E = hv

E is the energy of a particlar quantum under study.

h = planck,s constant which is usually 6.62607555 × 10^-34 js^-1

v = the frequency of the light.

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Answer:

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Explanation:

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3 years ago

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An electron in a cathode-ray beam passes between 2.5cm long parallel-plate electrodes that are 6.0mm apart. A 2.1mT, 2.5-cm-wide

Dmitry_Shevchenko [17]

Answer:

(a). The speed of electron is $1.56\times10^{7}\ m/s$ .

(b). The radius of electron is $4.2\ cm$

Explanation:

Given that,

Length = 2.5 cm

Distance = 6.0 mm

Magnetic field = 2.1 T

Potential difference = 700 V

(a). We need to calculate the electron's speed

Using formula of speed

$v=\sqrt{\dfrac{2eV}{m}}$

Put the value into the formula

$v=\sqrt{\dfrac{2\times1.6\times10^{-19}\times700}{9.1\times10^{-31}}}$

$v=15689290.81\ m/s$

$v=1.56\times10^{7}\ m/s$

(b). We need to calculate the radius of electron

Using formula of centripetal force

$\dfrac{mv^2}{r}=qvB$

$r=\dfrac{mv}{qB}$

Where,

m = mass of electron

v = speed of electron

r = radius

q = charge of electron

B = magnetic field

Put the value into the formula

$r=\dfrac{9.1\times10^{-31}\times1.56\times10^{7}}{1.6\times10^{-19}\times2.1\times10^{-3}}$

$r=0.042\ m$

$r=4.2\ cm$

Hence, (a). The speed of electron is $1.56\times10^{7}\ m/s$ .

(b). The radius of electron is 4.2 cm

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3 years ago

While riding in a hot air balloon, which is steadily decreasing at a speed of 1.14 m/s, you accidentally drop your cell phone. H

Ilia_Sergeevich [38]

Answer:

The distance covered by the balloon is 47.52 meters.

Explanation:

Given that,

Initial speed of the balloon, u = 1.14 m/

Let us assumed we need to find the distance covered by the balloon after t = 3 second. Let d is the distance covered by the balloon. It can be given by :

$d=ut+\dfrac{1}{2}at^2$

Here, a = g

$d=ut+\dfrac{1}{2}gt^2$

$d=1.14\times 3+\dfrac{1}{2}\times 9.8\times (3)^2$

d = 47.52 meters

So, the distance covered by the balloon is 47.52 meters. Hence, this is the required solution.

4 0

3 years ago

xIn the reaction A B + C + heat, ______. there is a net input of energy the potential energy of the products is greater than tha

kow [346]

Answer: Option (d) is the correct answer.

Explanation:

A chemical reaction in which heat energy is liberated is known as an exothermic reaction.

For example, $A \rightarrow B + C + Heat$

In an exothermic reaction, energy of reactants is more than the energy of products.

This means that potential energy of products is less than the potential energy of reactants.

Thus, we can conclude that in the reaction $A \rightarrow B + C + heat$ , the potential energy of the products is less than that of the reactant.

6 0

3 years ago