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3 years ago

What are two equations for the energy of light? Identify each variable.

Physics

1 answer:

lorasvet [3.4K]3 years ago

3 0

Answer:

E = hv

E = hf

Explanation:

there are basically two equations for energy in light.

E = hf

where E is the energy of the photons. the unit is joules

h = the planck's constant . the unit is joules second

f = frequency of light. the unit is Hertz

E = hv

E is the energy of a particlar quantum under study.

h = planck,s constant which is usually 6.62607555 × 10^-34 js^-1

v = the frequency of the light.

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NikAS [45]

Answer:

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b) time t = 19.27s

Explanation:

Note that;

ads = vdv

where

a is acceleration

s is distance

v is velocity

Given;

a = 6 + 0.02s

so,

$\int\limits^s_0 {a} \, ds = \int\limits^v_0 {v} \, dv\\ \int\limits^s_0 {6+0.02s} \, ds = \int\limits^v_0 {v} \, dv\\ 6s + \frac{0.02s^{2} }{2} = \frac{1}{2} v^{2} \\v = \sqrt{12s + 0.02s^{2} } .....................1 \\\\\\$

Remember that

$v = \frac{ds}{dt} \\\frac{ds}{v} = dt\\\int\limits^s_0 {\frac{ds}{\sqrt{12s+0.02s^{2} } } } \, ds = \int\limits^t_0 {} \, dt \\t= (5\sqrt{2} ) ln \frac{| [s + 300 + \sqrt{(s^{2} + 600s)} ] |}{300} .......2$

substituting s = 2km =2000m, into equation 1

v = 322.5m/s

substituting s = 2000m into equation 2

t = 19.27s

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asambeis [7]

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inessss [21]

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3 years ago

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kkurt [141]

Answer:

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