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3 years ago

A net charge of 5.0 coulombs passes a point on a

Physics

2 answers:

liraira [26]3 years ago

7 0

Answer: 1.0 x 10^2

Explanation:

cupoosta [38]3 years ago

6 0

Answer : The average value of current is $1.0\times 10^2\ A$ .

Explanation :

It is given that,

Net charge, q = 5 C

Time, t = 0.05 s

The electric current is defined as the rate of change of electric charge.

$I=\dfrac{q}{t}$

$I=\dfrac{5\ C}{0.05\ s}$

$I = 100\ A$

$I=1.0\times 10^2\ A$

The average current is $1.0\times 10^2\ A$ .

Hence, this is the required solution.

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A 2.2 kg model rocket is shot straight up in the air from the ground, with an initial velocity of 36.4 m/s. The rocket reaches i

alexandr1967 [171]

Answer:

Explanation:

Ignoring friction, the initial kinetic energy will convert to maximum potential energy at its highest point.

PE = KE

mgh = ½mv²

h = v²/2g

h = 36.4²/ (2(9.81))

h = 67.53109...

h = 67.53 m

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2 years ago

I need help with the question 8B

ratelena [41]

The answer of this is C

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3 years ago

Define newton's 3rd law of motion

soldier1979 [14.2K]

Answer:

For every action, there is an equal and opposite reaction.

Explanation:

Let's say I threw a ball on the wall. The image shows the instance the ball comes into contact with the wall.

If you would look at the image above,

- F1 and F2 are acting in opposite directions.

- They both have the same magnitude too.

F1 is the force of the ball on the wall (action force) and F2 is the force of the wall on the ball (reaction force). This is called an action-reaction pair.

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3 years ago

What is the net force of an object that has 7N to the left and right and 3N up

Stolb23 [73]

Answer:

the net force would be 3N in the upward direction since the two forces acting on the left and right of the object cancel out.

Explanation:

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3 years ago

An electric dipole consists of charges +2e and -2e separated by 0.82 nm. It is in an electric field of strength 3.2 x 10^6 N/C.

Zepler [3.9K]

Explanation:

It is given that,

An electric dipole consists of charges +2e and -2e separated by 0.82 nm

Charge, $q=2e=2\times 1.6\times 10^{-19}\ C=3.2\times 10^{-19}\ C$

Distance between charges, $d=0.82\ nm=0.82\times 10^{-9}\ m$

Electric field strength, $E=3.2\times 10^6\ N/C$

(a) The magnitude of the torque on the dipole is given by :

$\tau=p\times E\ sin\theta$

When dipole moment is parallel to the electric field, $\theta=0$

$\tau=p\times E\ sin(0)$

$\tau=0$

(b) When the dipole is perpendicular to the electric field, $\theta=90$

$\tau=pE\ sin(90)$

$\tau=qdE$ (Since, p = q × d)

$\tau=3.2\times 10^{-19}\times 0.82\times 10^{-9}\times 3.2\times 10^6$

$\tau=8.39\times 10^{-22}\ N.m$

(c) When the dipole moment is anti parallel to the electric field, $\theta=180$

$\tau=pE\ sin(180)$

Since, $sin\ 180=0$

$\tau=0$

Hence, this is the required solution.

8 0

3 years ago