Hello!
The molarity of the HBr solution is 0,172 M.
Why?
The neutralization reaction between LiOH and HBr is the following:
HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)
To solve this exercise, we are going to apply the common titration equation:
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Answer:
Explanation:
a )
1.25 g MgO contains .754 g of Mg .Rest will be O
so oxide = 1.25 - .754 = 0.496 g
ratio of magnesium to oxide = .754/.496 = 1.52
b) 1.25 g of MgO contains .754 g of Mg
534 g of MgO contains .754 x 534 / 1.25 g = 322.11 g
Barium nitrate and methane (CH4) are both soluble. They both will dissolve in water, however, barium nitrate will dissociate becoming barium 2+ ions and nitrate becoming NO3 1- ions. All nitrates are soluble and dissociate. CH4 is a weak base and does dissolves but doesn't dissociate. So in solubility terms.... they are both equally soluble just one happens to dissociate into its cations and anions. Hope this helps!
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We have to assume the gas behaves similar to an ideal gas and we can use the ideal gas law equation
PV = nRT
Where
P - pressure
V - volume - 7.5 L
n - number of moles - 1.0 mol
R - universal gas constant - 0.0821 L.atm/mol.K
T - temperature in kelvin
20 degrees celcius + 273 = 293 K
Substituting the values in the equation
P x 7.5 L = 1.0 mol x 0.0821 L.atm/mol.K x 293 K
P = 3.2 atm
The pressure exerted is 3.2 atm
