Answer:
Required time, t = 0.84 seconds
Explanation:
It is given that,
Initial speed of an object, u = 22 m/s
Final velocity of an object, v = 27 m/s
Acceleration, a = 5.93 m/s²
We have to find the time required for an object to go a speed of 22 m/s to a speed of 27 m/s. It can be solved by using first equation of motion as:
Where
t = time
t = 0.84 seconds
Hence, the time required for an object is 0.84 seconds.
Answer:
λ =8.57 μ m
Explanation:
Given that
Ey = 375 cos [kx − (2.20 × 10¹⁴ rad/s)t] N/C
Standard form
Ey=Eo cos[k x-ωt] N/C
By comparing the given equation with the standard wave equation
Eo = 375 N/C
ω = 2.20 × 10¹⁴ rad/s
We know that ω = 2 π f
f=3.50×10¹³ Hz
We know that the velocity given as
V = f λ
λ =Wavelength
V=Speed = 3 x 10⁸ m/s
λ =0.00000857 m ( 1 μ m = 10⁶ m)
λ =8.57 μ m
Answer:
Explanation:
solution solved below
