Question

How long will be required for an object to go from a speed of 22m/s to a speed of 27m/s if the acceleration is 5.93m/s^2 ?

Answer 1

Answer:

Required time, t = 0.84 seconds

Explanation:

It is given that,

Initial speed of an object, u = 22 m/s

Final velocity of an object, v = 27 m/s

Acceleration, a = 5.93 m/s²

We have to find the time required for an object to go a speed of 22 m/s to a speed of 27 m/s. It can be solved by using first equation of motion as:

$v=u+at$

Where

t = time

$t=\dfrac{v-u}{a}$

$t=\dfrac{27\ m/s-22\ m/s}{5.93\ m/s^2}$

t = 0.84 seconds

Hence, the time required for an object is 0.84 seconds.