given that snow is projected at an angle of 40 degree
It range is given as a = 19 ft
now we can use the formula of horizontal range
<u>so its initial speed must be 7.6 m/s</u>
How long will be required for an object to go from a speed of 22m/s to a speed of 27m/s if the acceleration is 5.93m/s^2 ?
1 answer:
Answer:
Required time, t = 0.84 seconds
Explanation:
It is given that,
Initial speed of an object, u = 22 m/s
Final velocity of an object, v = 27 m/s
Acceleration, a = 5.93 m/s²
We have to find the time required for an object to go a speed of 22 m/s to a speed of 27 m/s. It can be solved by using first equation of motion as:
Where
t = time
t = 0.84 seconds
Hence, the time required for an object is 0.84 seconds.
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