An empty beaker weighs 34.55 g.

What is the limiting reactant in the following equation? How much Fe2O3 will be produced if 2.1 g of Fe with 2.1 g of O2?

Verizon [17]

Answer:

Fe is limiting, and it will produce .0188 mols of Fe2O3

Explanation:

after you convert both Fe and O2 to mols by using their molar mass, you see there is less Fe than O2 so that is your limiting reactant. To find the amount of Fe2O3 you devide the limiting reactant by it's coefeciant (4) then multiply it by the products coefficant (2). Let me know if you have any questions

8 0

3 years ago

The other component of a solution is the part that’s does the dissolving. What is the name of this component

Allisa [31]

Answer:

liquid?

Explanation:

3 0

4 years ago

Determine the resulting pH when 75 mL of 0.05M HBr is reacted with 74 mL of 0.075 M KOH

Sunny_sXe [5.5K]

Answer:

pH = 12.08

Explanation:

H⁺ + OH⁻ → H₂O

First we calculate how many moles of each substance were added, using the given volume and concentration:

HBr ⇒ 0.05 M * 75 mL = 3.75 mmol HBr

KOH ⇒ 0.075 M * 74 mL = 5.55 mmol KOH

As HBr is a strong acid, it dissociates completely into H⁺ and Br⁻ species. Conversely, KOH dissociates completely into OH⁻ and K⁺ species.

As there are more OH⁻ moles than H⁺ moles (5.55 vs 3.75), we calculate how many OH⁻ moles remain after the reaction:

5.55 - 3.75 = 1.8 mmoles OH⁻

With that number of moles and the volume of the mixture, we calculate [OH⁻]:

[OH⁻] = 1.8 mmol / (75 mL + 74 mL) = 0.0121 M

With [OH⁻], we calculate the pOH:

pOH = -log[OH⁻] = 1.92

With the pOH, we calculate the pH:

pH = 14 - pOH

pH = 12.08

6 0

3 years ago

Hoon2. In words, describe how the changing positions of the sun, moon, and Earthleadthe different moon phases.

zysi [14]

As the Sun sets, the moon rises with the tide that faces the Earth fully exposed to sunlight. The moon has phases because of its orbit to Earth which causes the portion we see illuminated to change. The new moon occurs when the moon is positioned between the earth and the sun. at full moon and third quarter or called as the half moon, it happens when the moon is at a 90 degree angle with respect to the earth and the sun. crescent refers to the moon that is less than half illuminated by the sun. gibbous refers to more than half illuminated by the sun. waxing means growing or expanding in illumination and waning means shrinking or decreasing in illumination.

7 0

4 years ago

CaCO3(s) ⇄ CaO(s) + CO2(g) 0.100 mol of CaCO3 and 0.100 mol CaO are placed in an 10.0 L evacuated container and heated to 385 K.

Montano1993 [528]

Answer:

The final mass of CaCO3 is 10.68 grams

Explanation:

Step 1: Data given

Number of moles CaCO3 = 0.100 moles

Number of moles CaO = 0.100 moles

Volume = 10.0 L

When equilibrium is reached the pressure of CO2 is 0.220 atm. 0.250 atm of CO2 is added, while keeping the temperature constant

Step 2: The balanced equation

CaCO3(s) <==> CaO(s) + CO2(g)

Step 3: Calculate moles of CO2

n = PV/RT

⇒n = the initial number of moles CO2 = TO BE DETERMINED

⇒P = the pressure of CO2 at theequilibrium = 0.220 atm

⇒V = the volume of the container = 7.0 L

⇒R = the gas constant = 0.08206 L*atm / mol * K

⇒T = the temperature = 385 K

n = 0.220*7.0/(0.08206*385) = 0.0487 (mol)

this is the amount of CaCO3 which has been converted to CaO before pumping-in additional 0.225 atm CO2(g).

Step 4: Calculate moles CaCO3

After adding additional 0.250 atm CO2(g), the equilibrium CO2 pressure is still 0.220 atm. All this additional CO2 would completely convert to CaCO3:

n = PV/RT = 0.250*7.0/(0.08206*385) = 0.0554 moles

The total CaCO3 after equilibrium is reestablished is:

0.100 - 0.0487+ 0.0554 = 0.1067 mol

Step 5: Calculate mass CaCO3

Mass CaCO3 = 0.1067 moles * 100.09 g/mol

Mass CaCO3 = 10.68 grams

The final mass of CaCO3 is 10.68 grams

8 0

3 years ago