Fe 3+ + SCN- --> FeSCN 2+
<span>.......Fe 3+ .......SCN-.........FeSCN 2+ </span>
<span>I.......0.04..........0.001.............. </span>
<span>C........-x...............-x............. </span>
<span>E.....0.04-x.....0.001-x...........x </span>
<span>Keq = 203.4 = x / (0.04-x)(0.001-x) </span>
<span>203.4 = x / (x^2 - 0.041x + 4x10^-5) </span>
<span>203.4x^2 - 8.34x + 0.00094 = x </span>
<span>203.4x^2 - 9.34x + 0.00094 = 0 </span>
<span>x = -0.0001M or 0.0458M </span>
<span>so, using your Keq, there would be no SCN- or Fe 3+ left.....all would be in the form of FeSCN 2+</span>
B. compound a material that contains three elements joined in a fixed proportion
Answer:
0.093 mole of C₆H₁₂.
Explanation:
We'll begin by calculating the molar mass of C₆H₁₂. This can be obtained as follow:
Molar mass of C₆H₁₂ = (12×6) + (12×1)
= 72 + 12
= 84 g/mol
Finally, we shall determine the number of mole in 7.8 g of C₆H₁₂. This can be obtained as follow:
Molar mass of C₆H₁₂ = 84 g/mol
Mass of C₆H₁₂ = 7.8 g
Mole of C₆H₁₂ =?
Mole = mass / molar mass
Mole of C₆H₁₂ = 7.8 / 84
Mole of C₆H₁₂ = 0.093 mole
Thus, 7.8 g contains 0.093 mole of C₆H₁₂.
C not sure 100 percent but my best guess
Depending on what you are doing, virtual, or in school, you can contact your school and you ask them, or you can have your teacher, based on the subject, tutor you.
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