A beaker contains 0.42 L of water. The beaker’s volume Is ___milliliters.
2 answers:
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Molar mass of :
O2 = 16 * 2 = 32 g/mol
CO2 = 12 + 16 * 2 = 44 g/mol
<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
↓ ↓
2 moles 1 mole
2* 32 g O2 ----------> 1* 44 g CO2
x g O2 ------------> 10.0 g CO2
44 x = 2 * 32*10.0
44 x = 640
of O2
O2 = 16 * 2 = 32 g/mol
CO2 = 12 + 16 * 2 = 44 g/mol
<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
↓ ↓
2 moles 1 mole
2* 32 g O2 ----------> 1* 44 g CO2
x g O2 ------------> 10.0 g CO2
44 x = 2 * 32*10.0
44 x = 640
Answer:
The fraction of the volume of the atom that is taken up by the nucleus is .
The density of a proton is .
Explanation:
Diameter of the atom ,d = 2.50 Å
Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å
Volume of the sphere=
Volume of atom = V
..[1]
Diameter of the nucleus ,d' =
Radius of the nucleus ,r' = 0.5 d'=
Volume of nucleus = V'
..[2]
Dividing [2] by [1]
The fraction of the volume of the atom that is taken up by the nucleus is .
Diameter of the proton ,d =
1 m = 100 cm
Radius of the proton,r = 0.5 d=
Volume of the sphere=
Volume of atom = V
Mass of proton, m = 1.0073 amu =
Density of the proton : d
The density of a proton is .