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Deffense [45]
3 years ago
6

Explain the difference between what Isaac Newton and Louis de Broglie would have to say about the momentum of a particle that is

moving with a constant velocity. [velocity, mass, momentum, wavelength, Planck's constant]
Physics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer:

Explained

Explanation:

Newton would resort to the classical mechanics and say that the momentum of the particle that is moving with a constant velocity will be given by: momentum = mass x velocity

this approach will highlight the particle nature and will not be relativistic.

De-Broglie will say that the momentum of the particle is related to its associated matter wave and the relation between them is given by:

p = \frac{h}{\lambda}

where \lambda = wavelength of the matter wave associated to the particle, h = planck's constant

andp = \gamma\times mv

thus, this highlights the wave nature of the particle and is also relativistic.

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A child in a boat throws a 4.5kg package out horizontally with a speed of 13 m/s. Calculate the velocity of the boat immediately
Varvara68 [4.7K]

Answer:

0.78m/s

Explanation:

Now the momentum ensued by the boy throwing the package Is

Mass of package × velocity of package =4.5×13=58.5m/s

This momentum initiated a momentum on the boy-boat system

Total mass of the boy-boat system is 24+53=75kg

Let the velocity ensued by the boat be v.

Hence from conservation of momentum

58.5 =75×v

v= 58.5/75= 0.78m/s

4 0
3 years ago
Physics question A spacecraft descends vertically near the surface of Planet X. An upward thrust of 25.0kN from its engines slow
Evgesh-ka [11]
 F=m*a and m is constant on any planet 
25000-m*g=m*1.2 
10000-m*g=-m*0.80 
m*g is the weight 
25000/1.2-m*g/1.2=m 
10000/0.80-m*g/0.80=-25000/1.2+m*g/1.2 solve for m*g 
m*g=(10000/0.80+25000/1.2)/ (1/1.2+1/0.80) 
16 kN 
4 0
3 years ago
2. A driver brings a car traveling at 22 m/s to a stop in 2.0 seconds. What is the car's acceleration?
sveta [45]

Answer:

11 m/s²

Explanation:

Acc = v/t

Acc = 22 / 2.0

Acc = 11 m/s²

5 0
3 years ago
Read 2 more answers
Stan is driving north on his scooter at 8m/s, accelerates 11m/s (North) in 4s, drives a constant velocity for the next 15s, and
kow [346]

A) Acceleration: a_1 = 0.75 m/s^2, a_2 = 0, a_3 = -1.57 m/s^2

B) The total displacement is 209.5 m north

C) The average velocity is 8.06 m/s north

Explanation:

A)

Acceleration is defined as:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time taken for the velocity to change from u to v

Here we have:

- In the first  segment,

u = 8 m/s north

v = 11 m/s north

t = 4 s

So the acceleration is

a_1 = \frac{11-8}{4}=0.75 m/s^2 (north)

- In the second segment, Stan drives at a constant velocity: so the final velocity is equal to the initial velocity,

u = v

Therefore, the acceleration is zero: a_2 = 0

- In the third segment,

u = 11 m/s (north)

v = 0 (he comes to a stop)

t = 7 s

So the acceleration is

a=\frac{0-11}{7}=-1.57 m/s^2

And the negative sign means the acceleration is south, opposite to the direction of motion.

B)

In a uniformly accelerated motion, the displacement can be calculated as:

s=ut+\frac{1}{2}at^2

where

u is the initial velocity

a is the acceleration

t is the time

- For the first segment, we have

u = 0\\a = 0.75 m/s^2\\t=4 s

So the displacement is

s_1 = 0+\frac{1}{2}(0.75)(4)^2=6 m

- For the second segment, we have

u = 11 m/s\\a = 0\\t=15 s

So the displacement is

s_2 = (11)(15)+0=165 m

- For the third segment, we have

u = 11\\a = -1.57 m/s^2\\t=7 s

So the displacement is

s_3 = (11)(7)+\frac{1}{2}(-1.57)(7)^2=38.5 m

So the total displacement is:

s = 6 m + 165 m + 38.5 m = 209.5 m

In the north direction (positive direction)

C)

The average velocity is given by:

v=\frac{d}{t}

where

d is the total displacement

t is the total time

Here we have:

d = 209.5 m

t = 26 s

Therefore, the average velocity is

v=\frac{209.5}{26}=8.06 m/s (north)

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
The brightest star in the night sky in the northern hemisphere is Sirius. Its distance from Earth is estimated to be 8.7 light y
katen-ka-za [31]

Answer:5.11(10)^{13}miles

Explanation:

A light year is a unit of length and is defined as "the distance a photon would travel in vacuum during a Julian year at the speed of light at an infinite distance from any gravitational field or magnetic field. "

In other words: It is the distance that the light travels in a year.  

This unit is equivalent to 5.879(10)^{12}miles, which mathematically is expressed as:

1Ly=5.879(10)^{12}miles

Doing the conversion:

8,7Ly.\frac{5.879(10)^{12}miles}{1Ly}=5.11(10)^{13}miles  This is the distance from Earth to Sirius in miles.

4 0
3 years ago
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