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Deffense [45]
3 years ago
6

Explain the difference between what Isaac Newton and Louis de Broglie would have to say about the momentum of a particle that is

moving with a constant velocity. [velocity, mass, momentum, wavelength, Planck's constant]
Physics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer:

Explained

Explanation:

Newton would resort to the classical mechanics and say that the momentum of the particle that is moving with a constant velocity will be given by: momentum = mass x velocity

this approach will highlight the particle nature and will not be relativistic.

De-Broglie will say that the momentum of the particle is related to its associated matter wave and the relation between them is given by:

p = \frac{h}{\lambda}

where \lambda = wavelength of the matter wave associated to the particle, h = planck's constant

andp = \gamma\times mv

thus, this highlights the wave nature of the particle and is also relativistic.

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Answer:

B. Cart B

Explanation:

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3 years ago
How t calculate gravitational force
lions [1.4K]

Answer:

F=G(m1m2)/Rsquare if radius is given

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where,

f =gravitational force

G =gravitational constant

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m2=mass of another object

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3 years ago
Signal far enough ahead so other drivers in your vicinity can make adjustments to your change in speed and ___________.
3241004551 [841]

Answer:

DIRECTION

Explanation:

the answer of the blank will be DIRECTION

As the signal is far ahead so driver can make the decision of what he have to do either he can change direction or he can be on his same path.

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8 0
3 years ago
Help please!
JulsSmile [24]

3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:

(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v

where v is the velocity of the combined players. Solve for v :

450 kg•m/s - 320 kg•m/s = (155 kg) v

v = (130 kg•m/s) / (155 kg)

v ≈ 0.84 m/s

4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that

(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v

where v is the new velocity of the 4-kg ball. Solve for v :

30.6 kg•m/s - 5.2 kg•m/s = 9 kg•m/s + (4 kg) v

v = (16.4 kg•m/s) / (4 kg)

v = 4.1 m/s

7 0
2 years ago
Find the angle of refraction of a ray of light that enters a diamond (n=2.419) from air at an angle of 18.0° to the normal. ONLY
Tpy6a [65]

Answer:

n

Explanation:

hb

3 0
4 years ago
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