Answer:
The statement is true.
Both gravity and centrifugal force act on the Moon which causes it get pulled towards Earth (gravity) and get "flung away" so it doesn't hit us (centrifugal force).
Answer:
The required angle is (90-25)° = 65°
Explanation:
The given motion is an example of projectile motion.
Let 'v' be the initial velocity and '∅' be the angle of projection.
Let 't' be the time taken for complete motion.
Let 'g' be the acceleration due to gravity
Taking components of velocity in horizontal(x) and vertical(y) direction.
= v cos(∅)
= v sin(∅)
We know that for a projectile motion,
t =
Since there is no force acting on the golf ball in horizonal direction.
Total distance(d) covered in horizontal direction is -
d =
×t = vcos(∅)×
=
.
If the golf ball has to travel the same distance 'd' for same initital velocity v = 23m/s , then the above equation should have 2 solutions of initial angle 'α' and 'β' such that -
α +β = 90° as-
d =
=
=
=
.
∴ For the initial angles 'α' or 'β' , total horizontal distance 'd' travelled remains the same.
∴ If α = 25° , then
β = 90-25 = 65°
∴ The required angle is 65°.
Answer:
The velocity after 2 seconds can be found through:
V = u +a*t
Where V is final velocity, u is initial velocity, a is acceleration and t is time.
V = 0 + 2* 2= 4 meters/second
The distance (s) can be found through:
V^2= u^2 +2*a* s
Where V is final velocity, u is initial velocity, a is acceleration.
4^2= 0^2 + 2 *2*s
16= 0 + 4s
s= 4 meters
Distance (s) can also be found through:
s= ut + 1/2 at^2
s= 0+ 1/2 *2*2^2= 1 *2*2
s= 4 meters
Explanation:
Franklin must not drive through a flood for there may
no road at all under the water, unless he is familiar with the road and the
flowing water is below one foot.
Moreover, if negotiating a flooded section of
road, he must drive in the middle where the water will be at its shallowest and
he must not drive through water against approaching vehicle to consider other
drivers.
Answer:
the final velocity of the object is 53.04 m/s.
Explanation:
Given;
initial velocity of the projectile, u = 50 m/s
displacement of the object, d = 16 m
let the final velocity of the object = v
Apply the following kinematic equation to determine the final velocity of the projectile.
v² = u² + 2gd
v² = 50² + (2 x 9.8 x 16)
v² = 2813.6
v = √2813.6
v = 53.04 m/s
Therefore, the final velocity of the object is 53.04 m/s.