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adoni [48]
4 years ago
15

The three different states of matter are liquid, solid, and gas. A solid is something you can hold in your fingers, while a liqu

id is something you can hold in a cup. Gases are all around you, making up the air we all breathe. These three states are very different. However, liquids and gases do have some things in common. One of these is A) that liquids and gases are both less dense than solids. B) that liquids and gases are both more dense than solids. C) that liquids and gases both take the shape of their container. D) that liquids and gases do not take the shape of their container. Eliminate
Physics
2 answers:
prohojiy [21]4 years ago
5 0

A) Liquids and gases are both less dense than solids*.


*Except for the very special case of water.  Ice is less dense than liquid water.  That's why cubes float in soda, and bergs float in the ocean.

nika2105 [10]4 years ago
3 0

The answer is C. that liquids and gases both take the shape of their container.  

Think of it this way, if you take an ice cube and put it in your glass, it will stay in its shape and stay that way until it melts.  But if you put liquid or a gas into a glass, it will take the shape of the glass that it is put into.  

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State: the units for acceleration are?
krok68 [10]

A unit of acceleration needs a unit of length in the numerator
and a squared unit of time in the denominator.

Example:    meters / second²
                    feet / minute²
                    smoots / hour² 
                    furlongs / fortnight² .

Ideally, in order to completely describe an acceleration vector,
you also need to state a direction.
 
7 0
3 years ago
Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.40 kg mass to the
Aleks [24]

Answer:

Explanation:

mg = kx

k = mg/x

k = 0.40(9.8)/0.030

k = 130.66666...

k ≈ 130 N/m

4 0
3 years ago
An object has rotational inertia I. The object,initially at rest, begins to rotate with a constant angularacceleration of magnit
Tresset [83]

Answer:

L = I α t

Explanation:

given,                                          

rotational inertia = I              

initial velocity = ω₀                      

magnitude of acceleration = α      

angular momentum = L          

time = t                              

angular acceleration                                

\alpha = \dfrac{\omega-\omega_0}{t}

\alpha = \dfrac{\omega - 0}{t}

\alpha = \dfrac{\omega}{t}

ω = α t..............(1)

angular momentum                    

L = I ω                    

putting value from equation (1)

L = I α t                          

4 0
3 years ago
A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves o
aniked [119]

Correct question is;

A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves offers a damping force numerically equal to √2 times the instantaneous velocity. Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 7 ft/s. (Use g = 32 ft/s²)

Answer:

x(t) = 7te^(-2t√2)

Explanation:

We are given;

Weight; W = 8 lbs

mass; m = W/g

g = 32 ft/s²

Thus;

m = 8/32

m = ¼ slugs

From Newton's second law we can write the equation as;

m(d²x/dt²) = -kx - β(dx/dt)

Rearranging this, we have;

(d²x/dt²) + (β/m)(dx/dt) + (k/m)x = 0

Where;

β is damping constant = √2

k is spring constant = W/s

Where s = 8ft - 4ft = 4ft

k = 8/4

k = 2

Thus,we now have;

(d²x/dt²) + (√2/(¼))(dx/dt) + (2/(¼))x = 0

>> (d²x/dt²) + (4√2)dx/dt + 8x = 0

The auxiliary equation of this is;

m² + (4√2)m + 8 = 0

Using quadratic formula, we have;

m1 = m2 = -2√2

The general solution will be gotten from;

x_t = c1•e^(mt) + c2•t•e^(mt)

Plugging in the relevant values gives;

x_t = c1•e^(mt) + c2•t•e^(mt)

At initial condition of t = 0, x_t = 0 and thus; c1 = 0

Also at initial condition of t = 0, x'(0) = 7 and thus;

Since c1 = 0, then c2 = 7

Thus,equation of motion is;

x(t) = 7te^(-2t√2)

8 0
3 years ago
In the model of the hydrogen atom due to Niels Bohr, the electron moves around the proton at a speed of 3.3 × 106 m/s in a circl
irga5000 [103]

Answer:

1.5048\times 10^{-23}\ Am^2

Explanation:

q = Charge of proton = 1.6\times 10^{-19}\ C

r = Radius of circle = 5.7\times 10^{-11}\ m

v = Velocity of proton = 3.3\times 10^6\ m/s

Magnetic moment is given by

M=\frac{1}{2}qrv\\\Rightarrow M=\frac{1}{2}1.6\times 10^{-19}\times 5.7\times 10^{-11}\times 3.3\times 10^6\\\Rightarrow M=1.5048\times 10^{-23}\ Am^2

The magnetic moment associated with this motion is 1.5048\times 10^{-23}\ Am^2

5 0
3 years ago
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