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Aliun [14]
3 years ago
11

Which of the following lists elements in order of increasing malleability?

Chemistry
2 answers:
hodyreva [135]3 years ago
8 0

Malleability is the property due to which substances tend to hammered into thin sheets when pressure is applied. Malleability is observed in metal as the metal atoms are bound by metallic bonds. The layers of metal atoms can roll over each other without breaking the metal bond when pressure is applied. In the periodic table malleability decreases as the metallic nature decreases. Among the given metals Al is the most metallic element, followed by Zinc an Carbon is a non metal. Therefore, the order of increasing malleability will be C, Zn, Al


Trava [24]3 years ago
5 0
<h2>Answer:</h2>

The correct order of list of elements in order of increasing malleability is C, Zn, Al.

<h3>Explanation:</h3>
  • Flexibility/Malleability is a substance's capacity to distort under strain (compressive pressure). On the off chance that pliable, a material might be straightened into thin sheets by pounding or rolling. Malleable materials can be leveled into metal leaf.
  • This property is dominated in metals as compared to nonmetals.
  • As carbon is a nonmetal and zinc is a metal but rather of weak metallic properties than aluminum.
  • Hence malleability will increase from C to Zn to Al.
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What is that the theoretical yield of aluminum oxide I if 3.20 mol of aluminum metal is exposed to 2.70 mole of oxygen
photoshop1234 [79]

Answer:

163.2g

Explanation:

First let us generate a balanced equation for the reaction. This is shown below:

4Al + 3O2 —> 2Al2O3

From the question given, were were told that 3.2moles of aluminium was exposed to 2.7moles of oxygen. Judging by this, oxygen is excess.

From the equation,

4moles of Al produced 2moles of Al2O3.

Therefore, 3.2moles of Al will produce = (3.2x2)/4 = 1.6mol of Al2O3.

Now, let us covert 1.6mol of Al2O3 to obtain the theoretical yield. This is illustrated below:

Mole of Al2O3 = 1.6mole

Molar Mass of Al2O3 = (27x2) + (16x3) = 54 + 48 =102g/mol

Mass of Al2O3 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of Al2O3 = 1.6 x 102 = 163.2g

Therefore the theoretical of Al2O3 is 163.2g

8 0
3 years ago
How many grams of Na2So4 would be formed if 0.75 moles of NaOH reacted?
Nata [24]

Answer:

\boxed{\text{53 g }}

Explanation:

You don't give the reaction, but we can get by just by balancing atoms of Na.

We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                                 142.04  

             2NaOH + … ⟶ Na₂SO₄ + …  

n/mol:      0.75

1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.

Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH

= 0.375 mol Na₂SO₄

2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.

Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄

The reaction produces \boxed{\text{53 g }} of Na₂SO₄.

4 0
3 years ago
6 C + 3 H2 -&gt; C3H6, \Delta Δ ΔH= 49 kJ If 8.2 moles of C react with excess H2, what is the total change in energy?
Delicious77 [7]

I would like to know too

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4 years ago
The first chart shows the effect of the normal breakdown of material from reactants to products. The second chart shows the same
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Answer:

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Explanation:

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Answer:

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