Answer:
Explanation:
distance of shuttle from centre of the earth = radius of the orbit
= 6300 + 300 = 6600 km
= 6600 x 10³
Formula of time period of the satellite
T = 2π R /v₀ , v₀ is orbital velocity
v₀ = √gR , ( if height is small with respect to radius )
T = 2π R /√gR
= 2π√ R /√g
= 2 x 3.14 x √ 6600 x 10³ / √9.8
= 2 x 3.14 x 256.9 x 10 / 3.13
= 5154.41 s
= 5154.41 / 60 minutes
= 85.91 m
85.9 minutes.
2 ) No of sunrise per day = no of rotation per day
= 24 x 60 / 85.9
= 16.76
or 17 sunrises.
Answer:
x = 0.0873 m
Explanation:
given,
length of clothesline = 10 m
the line sags to create an angle that is 1 degree below the horizontal on each end.
As mass is hang at the center the angle made let the deflection be 'x'
as the shirt is hang at the center distance will be equal to 5 m.
now




x = 0.0873 m
Hence, the cloth line will be x = 0.0873 m from the original length of the clothesline.
False its atmosphere, lithosphere, hydrosphere, and boisphere
Answer:
v
2
=v
0
2
+2aΔxv, squared, equals, v, start subscript, 0, end subscript, squared, plus, 2, a, delta, x
Explanation:
Answer:
Cart A
Explanation:
Momentum can be computed by finding the product of mass and velocity. To solve this, you can use the formula below to find the greatest momentum:
p = mv
where:
p = momentum (kgm/s) m = mass (kg) v = velocity (m/s)
Because carts are moving along with the weights, we need to consider the whole system. This means that you need to add in the masses and the mass of the cart.
<u>Cart A:</u>
m = 200kg + 0 kg = 200 kg
v = 4.8 m/s
p = 200kg x 4.8 m/s = 960 kg-m/s
<u>Cart B:</u>
m = 200kg + 20 kg = 220 kg
v = 4.0 m/s
p = 220kg x 4.0 m/s = 880 kg-m/s
<u>Cart C:</u>
m = 200kg + 40 kg = 240 kg
v = 3.8 m/s
p = 240kg x 3.8 m/s = 912 kg-m/s
<u>Cart D:</u>
m = 200kg + 60 kg = 260 kg
v = 3.5 m/s
p = 260kg x 3.5 m/s = 910 kg-m/s
As you can see, Cart A has the greatest momentum.