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sashaice [31]
2 years ago
13

A kangaroo jumps straight up with an initial vertical velocity of 2.4m/s. We want to find the maximum height of the jump. We can

ignore air resistance. Which kinematic formula would be most useful to solve for the target unknown?

Physics
2 answers:
marishachu [46]2 years ago
8 0

Answer:

v  

2

=v  

0

2

​  

+2aΔxv, squared, equals, v, start subscript, 0, end subscript, squared, plus, 2, a, delta, x

Explanation:

Pavlova-9 [17]2 years ago
8 0

Answer:

D :)

Explanation:

Use this picture though

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3 years ago
Calculate the force at sea level that a boy of mass 50 kg exerts on a chair in which he is sitting.
kogti [31]

As per the question the mass of the boy is 50 kg.

The boy sits on a chair.

We are asked to calculate the force exerted by the boy on the chair at sea level.

The force exerted by boy on the chair while sitting on it is nothing else except the force of gravity of earth i.e the weight of the body .The direction of that force is vertically downward.

At sea level the acceleration due to gravity g = 9.8 m/s^2

Hence the weight of the boy w = mg  [m is the mass of the body]

we have m = 50 kg.

                             Hence w = 50 kg ×9.8 m/s^2

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Here newton [N] is the unit of force.





6 0
3 years ago
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If the net force on a block is zero
amm1812

If the net force on a block is zero, the block will move at constant velocity

Explanation:

We can answer this question by applying Newton's second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:

\sum F = ma (1)

where

\sum F is the net force on the object

m is its mass

a is its acceleration

In this problem, we have a block, and the net force on it is zero:

\sum F = 0

According to eq.(1), this also implies that

a=0

So, the acceleration of the block is zero.

However, acceleration is the rate of change of velocity of a body:

a=\frac{\Delta v}{\Delta t}

where \Delta v is the change in velocity in a time of \Delta t. Since the acceleration is zero, this means that \Delta v=0, and therefore the velocity of the object is constant.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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