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3 years ago

What is the relationship between gravity and pressure in a nebula?

2 answers:

8 0

The relationship between gravity and pressure in a nebula is that pressure balances gravity. The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity. The answer is B.

solmaris [256]3 years ago

6 0

Correct answer choice is :

B) Pressure balances gravity.

Explanation:

A nebula is an interstellar fog of dust, hydrogen, helium and other ionized gasoline. Basically, the nebula was a title for any scattered large object, including universes behind the Milky Way. Most nebulae are of a large size, some are numbers of light years in diameter. A nebula that is almost obvious to the human eye from earth would seem larger, but no brighter, from close by. The Orion Nebula, the glowing nebula in the sky that involves a range twice the width of the full Moon, can be observed with the naked eye but was dropped by early scientists.

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Why is oceanic crust sub-ducted under continental crust

tatuchka [14]

The oceanic crust slides under the continental crust due to the differences in their densities. The continental rust is more felsic (contains more silica) which makes it lighter than the oceanic crust which is more mafic (contains more fe and mg)

5 0

4 years ago

Read 2 more answers

A ball is thrown up at 30m/s from the ground. What is it s maximum height? How long did it take?

Rzqust [24]

Answer:

Maximum height reached by the ball thrown up at 30m/s is 3.06 seconds and the height reached is 45.9 meters

Explanation:

Given:

Initial velocity $u=30 \mathrm{m} / \mathrm{s}$

To find :

maximum height =?

time taken=?

Solution:

Step 1:Finding the time taken to reach the highest point:

The velocity of the ball at its highest ,final velocity v=0

Using the formula,

$v=u+a t$

Where a is acceleration due to gravity.Its value is $-9.8 m / s^{2}$

Substituting the values:

$0=30+(-9.8) t$

$-30=(-9.8) t$

$t=\frac{30}{9.8}$

$t=3.06 \mathrm{seconds}$

Step 2: finding the highest point

Using the formula

$v^{2}-u^{2}=2 a s$

where

s is the maximum highest.

Substituting values

$0^{2}-(30)^{2}=2(-9.8) s$

$0-900=(-19.6) s$

$-900=(-19.6) s$

$s=\frac{900}{19.6}$

$s=45.9 \text { meters }$

Result:

Thus the maximum height reached is 45.9 meters in 3.06 seconds

3 0

3 years ago

Read 2 more answers

A plate of uniform areal density is bounded by the four curves: where and are in meters. Point has coordinates and . What is the

Natali5045456 [20]

The question is incomplete. The complete question is :

A plate of uniform areal density $\rho = 2 \ kg/m^2$ is bounded by the four curves:

$y = -x^2+4x-5m$

$y = x^2+4x+6m$

$x=1 \ m$

$x=2 \ m$

where x and y are in meters. Point $P$ has coordinates $P_x=1 \ m$ and $P_y=-2 \ m$ . What is the moment of inertia $I_P$ of the plate about the point $P$ ?