What is the relationship between gravity and pressure in a nebula?

2 answers:

8 0

The relationship between gravity and pressure in a nebula is that pressure balances gravity. The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity. The answer is B.

solmaris [256]3 years ago

6 0

Correct answer choice is :

B) Pressure balances gravity.

Explanation:

A nebula is an interstellar fog of dust, hydrogen, helium and other ionized gasoline. Basically, the nebula was a title for any scattered large object, including universes behind the Milky Way. Most nebulae are of a large size, some are numbers of light years in diameter. A nebula that is almost obvious to the human eye from earth would seem larger, but no brighter, from close by. The Orion Nebula, the glowing nebula in the sky that involves a range twice the width of the full Moon, can be observed with the naked eye but was dropped by early scientists.

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What is The most basic unit of an Element on the Periodic Table

lesya [120]

Answer:

atom(which contains protons, neutrons and electrons)

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3 years ago

The normal force acting on an object and the force of static friction do zero work on the object. However the reason that the wo

spin [16.1K]

Answer:

The normal force is perpendicular to the displacement

The static friction force produces no displacement

Explanation:

Work Done By Special Forces

The work is a physical magnitude that measures the dot product of the force applied to an object by the displacement it produces in it.

$W=\vec F\ \vec r$

It can be written in its scalar version as

$W=F.d.cos\theta$

Being F and d the magnitudes of the force and displacement, and $\theta$ the angle between them

If the angle is zero, the work is at maximum, it the angle is 90°, the work is zero. If the angle is between 90° and 180°, the work is negative.

The normal force acts in the vertical direction when the object is being pushed horizontally. It means the angle between the force and the displacement is 90°, thus the work is

$W=N.d.cos90^o=0$

The work is zero because the force and the displacement are perpendicular

The static friction force exists only when the object is being applied a force of a magnitude not large enough to produce movement, i.e. the object is at rest. If the object is moved, the friction force is still present, but it's called dynamic friction force, usually smaller than the static.

Since in this case, there is no displacement, d=0, and the work is

$W=F_r(0)cos180^o=0$