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anzhelika [568]
3 years ago
8

What r semiconductors?

Physics
1 answer:
KengaRu [80]3 years ago
5 0
It is a solid substance that has a conductivity between that of an insulator and that of most metals, either due to the addition of an impurity or because of temperature effects
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What is the fault-current circuit breaker? Describe its function.
Nimfa-mama [501]

Answer:

A circuit breaker is a switching mechanism that interrupts the current that is irregular or fault. It is a mechanical system that interferes with high magnitude (fault) current flow and also performs a transfer operation. Hope this helps :)

Explanation:

4 0
3 years ago
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The unit for energy is the joule (j). If the energy content of an object is 1,000 J, but then later is found to be 900 J, what i
Dennis_Churaev [7]

Answer: the object transferred some of its energy to its surroundings.

Explanation:

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3 years ago
An object’s motion remains constant when acted upon by what?
igomit [66]

Answer:

An outside force

Explanation:

Newton's law an object in motion stays in motion an object at rest stays at rest unless acted on by an outside force.

6 0
3 years ago
Stars are formed in which of the following?
MAXImum [283]

    Stars are formed in <u>nebulas</u>, interstellar clouds of dust and gas.

6 0
3 years ago
A sound source is moving at 80 m/s toward a stationary listener that is standing in still air (a) Find the wavelength of the sou
Setler [38]

Answer:

a. wavelength of the sound, \vartheta = 1.315\vartheta_{o}

b. observed frequecy, \lambda = 0.7604\lambda_{o}

Given:

speed of sound source, v_{s} = 80 m/s

speed of sound in air or vacuum, v_{a} = 343 m/s

speed of sound observed, v_{o} = 0 m/s

Solution:

From the relation:

v = \vartheta \lambda        (1)

where

v = velocity of sound

\vartheta = observed frequency of sound

\lambda = wavelength

(a) The wavelength of the sound between source and the listener is given by:

\lambda = \frac{v_{a}}{\vartheta }         (2)

(b) The observed frequency is given by:

\vartheta = \frac{v_{a}}{v_{a} - v_{s}}\vartheta_{o}

\vartheta = \frac{334}{334 - 80}\vartheta_{o}

\vartheta = 1.315\vartheta_{o}                (3)

Using eqn (2) and (3):

\lambda = \frac{334}{1.315} = \frac{1}{1.315}\frac{v_{a}}{\vartheta_{o}}

\lambda = 0.7604\lambda_{o}

4 0
3 years ago
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