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zubka84 [21]
3 years ago
10

What is the value of work done on an object when a 70 newton force moves it 9.0 meters in the same direction as the force

Physics
2 answers:
Gnom [1K]3 years ago
4 0
W= F*D ==> W= 70 * 0.9= 63 J
olchik [2.2K]3 years ago
3 0
<span>Work, very simply, equals force times distance (when the force and distance are in the same direction. otherwise you get a little bit of trig added on) \[W=F*\Delta x\] W=70N * 9.0 m = 630 Nm = 630 J</span>
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Zanzabum

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2 years ago
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Alex777 [14]

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5 0
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If the result of your calculation of a quantity has si units kg•m^2/s^2•C, that quantity could be
Novosadov [1.4K]
It would be Joules.
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Workdone = Force * distance
Force = mass * acceleration
          = kg      *  ms⁻²
          = kgms⁻²

Distance = m

So, Force * distance
       kgms⁻² * m

Apply laws of indices that says
x² * x³ = x²⁺³ = x⁵

Therefore, It would be kgm²s⁻²
m¹ * m¹ = m¹⁺¹ = m²
s⁻² is also = s / 2





4 0
3 years ago
Read 2 more answers
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