Answer:
17500
Step-by-step explanation:
you just multiply it by 35 if it is pennies but you have to tell me if it is dimes or whatever
Answer:
(a)18
(b)1089
(c)Sunday
Step-by-step explanation:
The problem presented is an arithmetic sequence where:
- First Sunday, a=1
- Common Difference (Every subsequent Sunday), d=7
We want to determine the number of Sundays in the 120 days before Christmas.
(a)In an arithmetic sequence:

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.
Therefore, Aldsworth advertised 18 times.
(b)Next, we want to determine the sum of the first 18 terms of the sequence
1,8,15,...

The sum of the numbers of days published in all the advertisements is 1089.
(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.
Answer:
B
Step-by-step explanation:
Answer:
81
Step-by-step explanation:
1st History test: 73
2nd History test: 77
3rd History test: 81
4th History test: 85
5th History test: 89
73+77+81+85+89 = 405
405/5 = 81