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Maurinko [17]
3 years ago
14

How many moles are in 594 grams of Pb(NO3)4

Chemistry
1 answer:
irga5000 [103]3 years ago
6 0

Molar mass(Pb(NO3)4) =

= 207.2 × 1 + 14 × 4 + 16 × 12 =

= 455.2 g/mol

n(Pb(NO3)4) = 594 g ÷ 455.2 g/mol ~

~ 1.3 mol

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