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3 years ago

A bowling ball has a weight of 70 Newton’s on earth. What is it’s mass on earth? What’s it mass on the moon?

1 answer:

3 0

Weight = (mass) x (gravity)

70 N = (mass) x (9.8 m/s²)

Divide each side by (9.8 m/s²) , and you have

mass = 70 N / 9.8 m/s² = 7.14 kg.
___________________________

Mass on the moon:

Mass doesn't change. It's a number that belongs to the bowling ball,
no matter where the ball goes. If the mass of the bowling ball is 7.14 kg
anywhere, then it's 7.14 kg everywhere ... on Earth, on the moon, on Mars, rolling around in the trunk of my car, or floating in intergalactic space.

However, WEIGHT depends on the gravity wherever the ball happens to be
at the moment.

The acceleration of gravity on the moon is 1.622 m/s².
So the WEIGHT of the ball on the moon is

(7.14 kg) x (1.622 m/s²) = 11.58 Newtons

That's only about 16% of its weight on Earth.

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Which of the following must be true about the object labeled X in the circuit below?

Alex787 [66]

the answer is c and if I help you thank me

4 0

3 years ago

a liquid reactant is pumped through a horizontal, cylindrical, catalytic bed. The catalyst particles are spherical, 2mm in diame

natulia [17]

Answer:

The upper limit on the flow rate = 39.46 ft³/hr

Explanation:

Using Ergun Equation to calculate the pressure drop across packed bed;

we have:

$\frac{\delta P}{L}= \frac{150 \mu_oU(1- \epsilon )^2}{d^2p \epsilon^3} + \frac{1.75 \rho U^2(1-\epsilon)}{dp \epsilon^3}$

where;

L = length of the bed

$\mu$ = viscosity

U = superficial velocity

$\epsilon$ = void fraction

dp = equivalent spherical diameter of bed material (m)

$\rho$ = liquid density (kg/m³)

However, since U ∝ Q and all parameters are constant ; we can write our equation to be :

ΔP = AQ + BQ²

where;

ΔP = pressure drop

Q = flow rate

Given that:

9.6 = A12 + B12²

Then

12A + 144B = 9.6 -------------- equation (1)

24A + 576B = 24.1 --------------- equation (2)

Using elimination methos; from equation (1); we first multiply it by 2 and then subtract it from equation 2 afterwards ; So

288 B = 4.9

B = 0.017014

From equation (1)

12A + 144B = 9.6

12A + 144(0.017014) = 9.6

12 A = 9.6 - 144(0.017014)

$A = \frac{9.6 -144(0.017014}{12}$

A = 0.5958

Thus;

ΔP = AQ + BQ²

Given that ΔP = 50 psi

Then

50 = 0.5958 Q + 0.017014 Q²

Dividing by the smallest value and then rearranging to a form of quadratic equation; we have;

Q² + 35.02Q - 2938.8 = 0

Solving the quadratic equation and taking consideration of the positive value for the upper limit of the flow rate ;

Q = 39.46 ft³/hr

3 0

3 years ago

The line of latitude that is zero degrees latitude is the

Nuetrik [128]

Answer:

Equator

Explanation:

The equator is the line of latitude that separates the earth into the northern and southern hemisphere.Its magnitude is 0 degrees latitude. The equator and other lines of latitude are parallel to each other. The lines of longitude which is 0 degrees is known as the Greenwich meridian. The longitudinal lines however are not parallel as they converge at the poles.

7 0

3 years ago

Which statement is true about an object moving in a circular motion due to centripetal force, F, when the mass is doubled?

marshall27 [118]

Ans) A) Centripetal force will be doubled.

See centripetal force F = mv^2/r

That means centripetal force is directly proportional to the mass of the particle

So, if we double the mass, centripetal force will be increased by twofolds.

So, option A) is correct.

Now, looking at the other options,

B) says centripetal force is unaltered which is incorrect as centripetal force has been altered and increased twofold.

Option C) and D) reduces centripetal force which are also not possible here.

So, only Option A) is correct

4 0

4 years ago

Given that the electric potential is 7.3×10−2 V higher outside the cell than inside the cell, and that the cell membrane is 0.10

Pavel [41]

Answer:

Work to move on ion inside a cell = 1.168×10^-20J

Explanation:

Potential difference is a ratio of work done by a charge.

It is given as

◇V= Workdone ×charge= W/a

Workdone = V × q= (7.3×10^-2)×(1.6×10^-19)

W= 1.168×10^-20Joules

4 0

3 years ago