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3 years ago

A customer executive from Southeast Asia will visit your HQ facility and meet with your

Engineering

1 answer:

Rufina [12.5K]3 years ago

7 0

<u>Answer</u>:

Say no!

Explanation:

<u>Remember</u>, this scenario is an ethical dilemma. Been ethical implies doing what's professionally right, and as such saying no to that request is the right need to do. In the workplace a company's policies should be obeyed always by individual employees even though some may resent it.

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What is the steady-state value of the output of a system with transfer function G(s)= 6/(12s+3), subject to a unit-step input?

fenix001 [56]

Answer:

At steady state output will be 2

Explanation:

We have given transfer function $G(S)=\frac{6}{12S+3}$

Input is unit step so $X(S)=\frac{1}{S}$

We know that $G(S)=\frac{Y(S)}{X(S)}$ , here $Y(S)$ , is output

So output $Y(S)=G(S)\times X(S)$

$Y(S)=\frac{1}{S}\times \frac{6}{12S+3}$

Taking 12 common from denominator

$Y(S)=\frac{1}{2S(S+\frac{1}{4})}$

Now using partial fraction

$\frac{1}{2S(S+\frac{1}{4})}=\frac{A}{2S}+\frac{B}{(S+\frac{1}{4})}$

$\frac{1}{2S(S+\frac{1}{4})}=\frac{A(S+\frac{1}{4}+2BS)}{2S(S+\frac{1}{4})}$

$AS+\frac{A}{4}+2BS=1$

On comparing coefficient A=4 and B = -2

Putting the values of A and B in Y(S)

$Y(S)=\frac{4}{2S}-\frac{2}{S+\frac{1}{4}}$

Now taking inverse la place

$y(t)=2-2e^{\frac{-t}{4}}$

Steady state means t tends to infinite

So output at steady state = $y(t)=2-2e^{\frac{-\infty}{4}}$

$y(t)=2-0=2$

3 0

3 years ago

A wooden cylinder (0 02 x 0 02 x 0 1m) floats vertically in water with one-third of ts length immersed. a)-Determine the density

Anuta_ua [19.1K]

Answer:

a)- the density of wood is 333.33 Kg/m³

b)-unstable condition

c)-unstable condition

Explanation:

Given data

wooden cylinder = 0.02m x 0.02m x 0.1m

floating = 1/3 × Length

to find out

density of wood, is it stable condition and wood would float stably in alcohol with density 700 kg/m3

Solution

First we find out density of wood

we know density of water is 1000 kg/m³

and we know wood float 1/3 of length so fraction of density will be

density of wood/ density of water = 1/3

density of wood = 1/3 × density of water

density of wood = 1/3 × 1000 = 333.33 Kg/m³

Now in 2nd part we know for stable condition in partially submerged of body the metacentric height is greater than the centroid of body

we check these condition now,

metacentric height (GM)= I/v

I = ( 0.02 × 0.02³ / 12 )

v = ( 0.02 × 0.02 × 0.1 )

(GM)= I/v = ( 0.02 × 0.02³ / 12 ) / ( 0.02 × 0.02 × 0.1 ) = 0.000333

and we know centroid of body (BM) = 0.05 - 0.033 = 0.017

we know height is 0.1m so G act at 0.05 and B act at (0.1 × 0.3 ) = 0.033

we can see that now metacentric height is less than centroid of body so our body is unstable condition

Now in 3rd part we use alcohol so we calculate ratio of density of wood and density of alcohol i.e. = 333.33 / 700 = 0.48

so now our new G will be 0.05 and B will be (0.1 × 0.48 ) = 0.048

metacentric height (GM)= I/v = ( 0.02 × 0.02³ / 12 ) / ( 0.02 × 0.02 × 0.1 ) = 0.000333

centroid of body (BM) = 0.05 - 0.048 = 0.002

we can see that now metacentric height is less than centroid of body so our body is unstable condition

5 0

3 years ago

A pressure gage connected to a tank reads 50 psi at a location where the barometric reading is 29.1 inches Hg. Determine the abs

Effectus [21]

Answer:

Absolute pressure , P(abs)= 433.31 KPa

Explanation:

Given that

Gauge pressure P(gauge)= 50 psi

We know that barometer reads atmospheric pressure

Atmospheric pressure P(atm) = 29.1 inches of Hg

We know that

1 psi = 6.89 KPa

So 50 psi = 6.89 x 50 KPa

P(gauge)= 50 psi =344.72 KPa

We know that

1 inch = 0.0254 m

29.1 inches = 0.739 m

Atmospheric pressure P(atm) = 0.739 m of Hg

We know that density of Hg = $13.6\times 10^3\ kg/m^3$

P = ρ g h

P(atm) = 13.6 x 1000 x 9.81 x 0.739 Pa

P(atm) = 13.6 x 9.81 x 0.739 KPa

P(atm) =98.54 KPa

Now

Absolute pressure = Gauge pressure + Atmospheric pressure

P(abs)=P(gauge) + P(atm)

P(abs)= 344.72 KPa + 98.54 KPa

P(abs)= 433.31 KPa

3 0

3 years ago

A slight breeze is blowing over the hot tub above and yields a heat transfer coefficient h of 20 W/m2 -K. The air temperature is

patriot [66]

Answer:4050 W

Explanation:

Given

Heat transfer Coefficient(h)= $20 W/m^2-K$

Air temperature =75 F

surface area(A)= $7.5 m^2$

Temperature of hot tube is 102 F

We know heat transfer due to convection is given by

$Q=hA\left ( \Delta T\right )$

$Q=20\times 7.5\left ( 102-75\right )=4050 W$

7 0

3 years ago

Which situation might cause potential hazards at a construction site?

nata0808 [166]

Answer:

D. protruding steel rebars .. #answerwithquality #BAL

5 0

3 years ago

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