Lo siento, no sé qué estás diciendo.
Answer:
is this a question for hoework
Answer:
final temperature is 424.8 K
so correct option is e 424.8 K
Explanation:
given data
pressure p1 = 1 bar
pressure p2 = 5 bar
index k = 1.3
temperature t1 = 20°C = 293 k
to find out
final temperature t2
solution
we have given compression is reversible and has an index k
so we can say temperature is
![\frac{t2}{t1}= [\frac{p2}{p1}]^{\frac{k-1}{k} }](https://tex.z-dn.net/?f=%5Cfrac%7Bt2%7D%7Bt1%7D%3D%20%5B%5Cfrac%7Bp2%7D%7Bp1%7D%5D%5E%7B%5Cfrac%7Bk-1%7D%7Bk%7D%20%7D)
...........1
put here all these value and we get t2
![\frac{t2}{293}= [\frac{5}{1}]^{\frac{1.3-1}{1.3} }](https://tex.z-dn.net/?f=%5Cfrac%7Bt2%7D%7B293%7D%3D%20%5B%5Cfrac%7B5%7D%7B1%7D%5D%5E%7B%5Cfrac%7B1.3-1%7D%7B1.3%7D%20%7D)
t2 = 424.8
final temperature is 424.8 K
so correct option is e
Scientific notation is another way to write a number. In scientific notation, the letter E is used to mean "10 to the power of." For example, 1.314E+1 means 1.314 * 101 which is 13.14 . Scientific notation is merely a format used for input and output.
Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb
