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Scrat [10]
3 years ago
7

A beam has been fixed to the floor by the pin at B and the roller at A as shown in figure 1 below.​

Engineering
1 answer:
ahrayia [7]3 years ago
3 0
What figure below???
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Stream Piracy – Kaaterskill, NY. Check and double-click the Problem 15 folder. The dark blue and orange streams highlight the pr
baherus [9]

Answer:

b. The pirating streams are eroding headwardly to intersect more of the other streams’ drainage basins, causing water to be diverted down their steeper gradients.

Explanation:

From the Kaaterskill NY 15 minute map (1906), this shows two classic examples of stream capture.

The Kaaterskill Creek flow down the east relatively steep slopes into the Hudson River Valley. While, the Gooseberry Creek is a low gradient stream flowing down the west direction which in turn drains the higher parts of the Catskills in this area.

However, there is Headward erosion of Kaaterskill Creek which resulted to the capture of part of the headwaters of Gooseberry Creek.

The evidence for this is the presence of "barbed" (enters at obtuse rather than acute angle) tributary which enters Kaaterskill Creek from South Lake which was once a part of the Gooseberry Creek drainage system.

It should be noted again, that there is drainage divide between the Gooseberry and Kaaterskill drainage systems (just to the left of the word Twilight) which is located in the center of the valley.

As it progresses, this divide will then move westward as Kaaterskill captures more and more of the Gooseberry system.

5 0
3 years ago
1: A baseball is hit 4 feet above the ground leaves the bat with an initial speed of 98 ft/sec at an angle of 0 45 is caught by
zvonat [6]

Answer:

299.36 feet

Explanation:

To \ find  \   the  \ distance \  of  \ the  \ ball \  from  \ the \ home  \ plate.  \\ \\ From  \ the  \ given  \ information:

Height \ h = 4 \ ft

Initial \ speed \ V_o = 98 \ ft/s ec

The  \ angle \  \theta = 45^0

Acceleration \ due \ to \ gravity (g)= 32.2 \ ft/s

U_x = V_o \ cos 45 = \dfrac{98}{\sqrt{2}}

U_y = V_o \ sin 45 = \dfrac{98}{\sqrt{2}}

So;

S_y = u_y t - \dfrac{1}{2}gt^2

-1 =\dfrac{98}{\sqrt{2}}t - \dfrac{1}{2}*32*1.85t^2

By solving:

t_1 = 4.32 \ sec

Thus;

horizontal \ distance = U_x t

= \dfrac{98}{\sqrt{2}}\times 4.32

\mathbf{=299.36  \ feet}

\mathbf{Thus \ , the  \  distance \ from \  the  \ home  \ plate \  =  \ 299.36  \ feet}

5 0
3 years ago
Many jacks use hydraulic power. True or False
34kurt

Answer:true

Explanation:

7 0
3 years ago
A well-insulated, full, water tank containing 197 kg of water initially at 43.9°C is being supplied with 16.7°C water at a rate
joja [24]

Answer:

idk sorry

Explanation:

4 0
3 years ago
The driveshaft of an automobile is being designed to transmit 134 hp at 2900 rpm. Determine the minimum diameter d required for
Misha Larkins [42]

Answer:

The minimum diameter is 1.344 in

Explanation:

The angular speed of the driveshaft is equal to:

w=\frac{2\pi N}{60}

Where

N = rotational speed of the driveshaft = 2900 rpm

w=\frac{2\pi *2900}{60} =303.69rad/s

The torque in the driveshaft is equal to:

\tau=\frac{P}{w}

Where

P = power transmitted by the driveshaft = 134 hp = 73700 lb*ft/s

\tau=\frac{73700}{303.69}  =242.68lb*ft

The minimum diameter is equal to:

d_{min} =(\frac{16T}{\pi *\tau } )^{1/3}

Where

T = shear stress = 6100 psi

τ = 242.68 lb*ft = 2912.16 lb*in

d_{min} =(\frac{16*2912.16}{\pi *6100} )^{1/3} =1.344in

4 0
3 years ago
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