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3 years ago

What is the animal behavior where organisms imitate another organism or environment in some way?

Physics

1 answer:

aksik [14]3 years ago

8 0

Mimicry. This is when oraganisms imitate another oraganism whether it be physical or behavoioral.

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A conductor is formed into a loop that encloses an area of 1m^2. The loop is oriented at a angle 30 degree with the xy plane. A

choli [55]

Answer:

$\frac{dB}{dt} = 11.55 T/s$

Explanation:

As we know that flux of magnetic field from the closed loop is given by

$\phi = BAcos30[tex]now by Faraday's law we know[tex]EMF = \frac{d\phi}{dt}$

now we will have

$EMF = Acos30\frac{dB}{dt}$

now we have

$A = 1 m^2$

EMF = 10 Volts

$10 = 1 (cos30)\frac{dB}{dt}$

$\frac{dB}{dt} = \frac{20}{\sqrt3}$

$\frac{dB}{dt} = 11.55 T/s$

5 0

3 years ago

Match the term with the correct question it answers.

Serga [27]

Answer:

1) Where

2) How far

3) How far, in what direction

4) How fast

5) How fast,in what direction

4 0

3 years ago

A uniform drawbridge must be held at a 37 ? angle above the horizontal to allow ships to pass underneath. The drawbridge weighs

iVinArrow [24]

Answer:

Explanation:

a ) Let T be tension in the horizontal cable .

Taking torque about hinge of weight and tension

45000 x 7 x cos37 = 3.5 sin 37 x T

T = 119431 N

b ) If R be the reaction force on the hinge

R sin 37 = 45000 ( vertical force balancing each other )

R = 74775 N

c ) The direction of R will be along the bridge

d ) Moment of inertia of bridge

I = Ml² / 3 = (45000 / 9.8 ) x 14² / 3

= 300000.

When cable breaks , the weight creates a torque about the hinge will creates angular acceleration

Torque by weight about the hinge

= 45000 x 7 x cos 37

= 251570

angular acceleration = torque / moment of inertia

= 251570 / 300000

= .84 radian / s²

4 0

3 years ago

A shuttle bus slows down with an average acceleration of -2.4 m/s2. How long does it

olganol [36]

Answer:

$\boxed {\boxed {\sf 3.75 \ seconds }}$

Explanation:

Average acceleration is found by dividing the change in acceleration by the time.

$a=\frac{ v_f-v_i}{t}$

The shuttle bus has an acceleration of -2.4 meters per square second. It slows from 9.0 meters per second to rest, or 0 meters per second. Therefore:

$a= -2.4 \ m/s^2 \\v_f= 0 \ m/s \\v_i= 9 \ m/s$

Substitute the values into the formula.

$-2.4 \ m/s^2=\frac{0 \ m/s - 9 \ m/s}{t }$

Solve the numerator.

$-2.4 \ m/s^2 = \frac{-9 \ m/s}{t}$

We want to solve for t, the time. We have to isolate the variable. Let's cross multiply.

$\frac{-2.4 \ m/s^2}{1} = \frac{-9 \ m/s}{t}$

$-9 \ m/s *1= -2.4 \ m/s^2 *t$

$-9 \ m/s=-2.4 m/s^2*t$

t is being multiplied by -2.4. The inverse of multiplication is division, so divide both sides by -2.4

$\frac{-9 \ m/s }{-2.4 \ m/s^2} =\frac{ -2.4 \ m/s^2*t}{-2.4 \ m/s^2}$

$\frac{-9 \ m/s }{-2.4 \ m/s^2} =t$

$3.75 \ s=t$

It takes 3.75 seconds.

4 0

3 years ago

9. A 227 kg object is moved a distance of 2.4 m forward by a force. If 686 J of work is done on the object, what is the object’s

Korolek [52]

1.259ms^2

Explanation:

since, WORK DONE = FORCE*DISTANCE

AND, FORCE=MASS*ACCELERATION

SO, THE WORK DONE BECOMES=MASS*ACCELERATION*DISTANCE

ACCELERATION=WORK/(MASS*DISTANCE)

AND, WORK=686J

MASS=227kg

DISTANCE=2.4m

THEREFORE, ACCELERATION=686/(227*2.4)

=686/544.8

=1.259ms^2

4 0

3 years ago