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blagie [28]
3 years ago
5

Carbon dioxide (CO2) is a gaseous compound. Calculate the percent composition of this compound. Answer using three significant f

igures.
What is the percent by mass of carbon?
%

What is the percent by mass of oxygen?
%
Chemistry
1 answer:
Ilya [14]3 years ago
8 0

Answer:

27.3%

72.7%

Explanation:

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In which way does a balanced chemical equation demonstrate the conservation of matter?
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Answer:

A. It shows the same number of atoms of each element on both sides of the equation.

Explanation:

A balanced chemical equation demonstrates the conservation of matter by showing the number of atoms of each element on both sides of the equation or expression.

According to the law of conservation of matter, matter is neither created nor destroyed in the course of a chemical reaction but atoms are rearranged.

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3 years ago
A key step in the extraction of iron from its ore isFeO(s) + CO(g) ⇄ Fe(s) + CO₂(g) Kp = 0.403 at 1000°CThis step occurs in the
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A key step in the extraction of iron from its ore isFeO(s) + CO(g) ⇄ Fe(s) + CO₂(g) Kp = 0.403 at 1000°CThis step occurs in the 700°C to 1200°C zone within a blast furnace. the partial pressure of CO2 at equilibrium is 1.58 atm.

The complete reaction of the problem, for better illustration, is

FeO(s) + CO(g) <--> Fe(s) + CO2(g)

The double-tailed arrow signifies that the reaction is in a dynamic chemical equilibrium. When the system is in equilibrium, the forward and the backward reaction rates have an equal ratio of Kp = 0.403 at 1000°C. The formula for Kp is

Kp = [partial pressure of products]/[partial pressure of reactants]

So, first, let's find the partial pressure of the compounds in the reaction.

                     FeO(s) + CO(g) <--> Fe(s) + CO2(g)

Initial                 x            1.58            0           0

Change           -1.58        -1.58       +1.58     +1.58

------------------------------------------------------------------

Equilbrium      x-1.58          0             1.58       1.58

Kp = [(1.58)(1.58)]/[(x-1.58)] = 0.403

x = 7.77 atm (this is the amount of excess FeO)

Therefore, the partial pressure of CO2 at equilibrium is 1.58 atm. There is no more CO because it has been consumed due to excess FeO.

To know more about partial pressure of CO2 at equilibrium

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