Answer:
B) 12.1 m/s
Explanation:
Sum of the forces in the y direction:
∑F = ma
N − mg = 0
N = mg
Sum of the forces in the radial direction:
∑F = ma
F = m v² / r
Nμ = m v² / r
Substituting and solving for v:
mgμ = m v² / r
gμ = v² / r
v = √(gμr)
Given that μ = 0.200 and r = 75.0 m:
v = √(9.81 m/s² × 0.200 × 75.0 m)
v = 12.1 m/s
Answer:
<em>erosion, physical reactions, chemical reactions, and gravity</em>
Hope this helps you out, dear. Have a beautiful day!!
Answer:
0.0327 m
Explanation:
m = 2 kg
ω = 24 rad/s
A = 0.040 m
Let at position y, the potential energy is twice the kinetic energy.
The potential energy is given by
U = 1/2 m x ω² x y²
The kinetic energy is given by
K = 1/2 m x ω² x (A² - y²)
Equate both the energies as according to the question
1/2 m x ω² x y² = 2 x 1/2 m x ω² x (A² - y²)
y² = 2 A² - 2 y²
3y² = 2A²
y² = 2/3 A²
y = 0.82 A = 0.82 x 0.040 = 0.0327 m
Answer:
The value of leaking rate in the question is repeated. By searching on the web I could find the correct value wich is 0.002h^2 m^3 /min.
The depth of the water has to be equal to 7.07 m in order to have a stationary volume.
Explanation:
In order to have a stationary water level the flow of water that comes into the tank (0.1 m^3/min) must be equal to the flow of water that goes out of the tank (0.002*h^2 m^3/min), therefore:
0.002*h^2 = 0.1
h^2 = 0.1/0.002
h^2 = 50
h = sqrt(50) = 7.07 m
