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3 years ago

What is the potential energy of an 18 kg object with a height of 15 m?

Chemistry

2 answers:

Mila [183]3 years ago

8 0

302 (mgh) is the answer

kicyunya [14]3 years ago

5 0

Explanation:

Potential Energy :

PE = m x g x h

PE= 18 x 10 x 15

PE= 2700Joule...

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A burner is placed below the right side of a beaker. Which image shows the motion of the liquid that will result?

matrenka [14]

Answer:

the result will be the whole surface of the liquid boilling

Explanation:

3 0

3 years ago

A sample of 87.6 g of carbon is reacted with 136 g of

Vadim26 [7]

Answer:

A. fluorine, 1.79 moles

Explanation:

Given parameters:

Mass of carbon = 87.7g

Mass of fluorine gas = 136g

Unknown:

The limiting reactant and the maximum amount of moles of carbon tetrafluoride that can be produced = ?

Solution:

Equation of the reaction:

C + 2F₂ → CF₄

let us find the number of the moles the given species;

Number of moles = $\frac{mass}{molar mass}$

C; molar mass = 12;

Number of moles = $\frac{87.7}{12}$ = 7.31moles

F; molar mass = 2(19) = 38g/mol

Number of moles = $\frac{136}{38}$ = 3.58moles

So;

From the give reaction:

1 mole of C requires 2 moles of F₂

7.31 moles of C will then require 2 x 7.31 moles of F₂ = 14.62moles

But we have 3.58 moles of the F₂;

Therefore, the reactant in short supply is F₂ and it is the limiting reactant;

So;

2 moles of F₂ will produce mole of CF₄

3.58 moles of F₂ will then produce $\frac{3.58}{2}$ = 1.79moles of CF₄

6 0

3 years ago

Which is TRUE of the products in this combustion reaction? 4Fe + 3O2 2Fe2O3

ycow [4]

The only true answer is A.

products are on the right side of the reaction

products and reactants don't necessarily have same physical or chemical properties

It is the reactants that <span>are the atoms, molecules, or compounds that participate in the reaction.</span>

7 0

3 years ago

Read 2 more answers

The reaction of NO2 with ozone produces NO3 in a second-order reaction overall.

Brilliant_brown [7]

Answer : The rate of reaction is,

$Rate=4.77\times 10^{-19}M/s$

The appearance of $NO_3$ is, $4.77\times 10^{-19}M/s$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$NO_2(g)+O_3(g)\rightarrow NO_3(g)+O_2(g)$