Answer: The partial pressure of oxygen is 187 torr.
Explanation:
According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.
where, x = mole fraction
= total pressure
,
,
Thus the partial pressure of oxygen is 187 torr.
There are 0.454 kg in 1 lb
Cross multiply
0.454 kg = 1 lb
X kg. = 50 lb
50* 0.454 = 22.7 kg
Answer : 22.7 kg in 50 lbs
Well from my research I've calculated that pH + pOH = 14.00. in conclusion
pOH = 14.0 - 4.0 and so forth that equals 10.0 your welcome