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vodomira [7]
3 years ago
10

A 500 gram piece of metal had a volume of 2.75cm3. What is it’s density

Chemistry
1 answer:
beks73 [17]3 years ago
8 0

Answer:

181.82 g/cm3

Explanation:

density is mass / volume so it is 500 / 2.75=181.82 g/cm3

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Number of electrons the atom my accept from another atom?
ZanzabumX [31]

Answer:

Yes atoms can accept the electrons from another atom like

Chlorine accept electron from hydrogen.

Explanation:

8 0
3 years ago
What is the engine piston displacement in liters of an engine who’s displacement is listed as 430 in.²
sergeinik [125]

For an engine whose displacement is listed as 430 in.², the engine piston displacement in liters is mathematically given as

PD= 7.37 L  

<h3>What is the engine piston displacement in liters of an engine whose displacement is listed as 430 in.²?</h3>

Generally, the equation for the dimensional analysis method,\, we convert in to L is mathematically given as

l*(v/l)*l/v

Therefore,  piston displacement

PD=(450 in3) . (1 dm3 / 61.024 in3) . (1 L / 1 dm3)

PD= 7.37 L  

In conclusion, piston displacement

PD= 7.37 L  

Read more about volume

brainly.com/question/1578538

#SPJ1

6 0
3 years ago
A 32.4 L gas sample at STP is compressed to a volume of 28.4 L, and the temperature is increased to 352 K. What is the new press
Sindrei [870]

Answer:

1.47 atm

Explanation:

Step 1: Given data

  • Initial volume (V₁): 32.4 L
  • Initial pressure (P₁): 1 atm (standard pressure)
  • Initial temperature (T₁): 273 K (standard temperature)
  • Final volume (V₂): 28.4 L
  • Final pressure (P₂): ?
  • Final temperature (T₂): 352 K

Step 2: Calculate the final pressure of the gas

We can calculate the final pressure of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

P₂ = P₁ × V₁ × T₂ / T₁ × V₂

P₂ = 1 atm × 32.4 L × 352 K / 273 K × 28.4 L = 1.47 atm

7 0
3 years ago
How much energy is transferred from a plant to an herbivore that eats it? A. 5% B. 10% C. 20% D. 90%
Tema [17]

Answer:

B. 10%

Explanation:

6 0
3 years ago
What organic product would be formed from the reaction of 1-bromo-2-methylpropane (isobutyl bromide), (ch3)2chch2br, with mg, et
miskamm [114]

The reaction of 1-bromo-2-methylpropane (isobutyl bromide), (CH_3)_2CHCH_2Br, with Mg, and Et_2O results in the formation of an adduct of formula (CH_3)_2CHCH_2MgBr known as grignard reagent, an organometallic reagent, which on reacting with H_3O^{+} results in the formation of isobutane.

The reaction is shown in the image.

4 0
3 years ago
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