Medicine to a patient. That should be calculated based on weight, strength/dosage and possibly other factors
1. C. Gravitational attraction exists between the two objects.
Explanation:
Gravitational attraction is always exerted between two objects which have mass, and its magnitude is given by:
![F=G\frac{m_1 m_2}{r^2}](https://tex.z-dn.net/?f=F%3DG%5Cfrac%7Bm_1%20m_2%7D%7Br%5E2%7D)
where G is the gravitational constant, m1 and m2 the masses of the two objects, and r the separation between them. Since the two objects have for sure non-zero masses m1 and m2, even if they are 20 miles apart, the value of the gravitational attraction F is non-zero, so the correct answer is C.
2. D. Two atoms come together to form a molecule.
Explanation:
this outcome is actually caused by the electrostatic forces between the two atoms, not by gravitational force. In fact, gravitational force becomes relevant only when the masses of the two objects involved are large enough: this is the case for planets, stars, galaxies, and objects in the universe. However, two atoms have very small masses, so the gravitational force between them is really negligible. On this smaller scales, the electrostatic force is much stronger than the gravitational force, so the electrostatic force is the real responsible for the formation of bonds between atoms.
As per above given data
initial velocity = 19.3 km/s
final velocity = - 18.8 km/s
now in order to find the change in velocity
![\Delta v = v_f - v_i](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20v_f%20-%20v_i)
![\Delta v = -18.8 - 19.3](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20-18.8%20-%2019.3)
![\Delta v = -38.1 km/s](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20-38.1%20km%2Fs)
![\Delta v = -3.81 * 10^4 m/s](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20-3.81%20%2A%2010%5E4%20m%2Fs)
Part b)
Now we need to find acceleration
acceleration is given by formula
![a = \frac{\Delta v}{\Delta t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5CDelta%20v%7D%7B%5CDelta%20t%7D)
given that
![\Delta v =- 3.81 * 10^4 m/s](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D-%203.81%20%2A%2010%5E4%20m%2Fs)
![\Delta t = 2.07 years = 6.53 * 10^7 s](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%202.07%20years%20%3D%206.53%20%2A%2010%5E7%20s)
now the acceleration is given as
![a = \frac{-3.81 * 10^4}{6.53 * 10^7}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B-3.81%20%2A%2010%5E4%7D%7B6.53%20%2A%2010%5E7%7D)
![a = - 5.84 * 10^{-4}m/s^2](https://tex.z-dn.net/?f=a%20%3D%20-%205.84%20%2A%2010%5E%7B-4%7Dm%2Fs%5E2)
so above is the acceleration
Complete Question
The complete question is shown on the first uploaded image
Answer:
the value of ![y = 13.3](https://tex.z-dn.net/?f=y%20%3D%2013.3)
Explanation:
From the question we are told that
The equation is (x + y = 40)
The first value of x is ![x_1 = 26.7](https://tex.z-dn.net/?f=x_1%20%3D%20%2026.7)
The second equation is (0.75x + 1.5y = 40)
So substituting ![x_1](https://tex.z-dn.net/?f=x_1)
![26.7 + y = 40](https://tex.z-dn.net/?f=26.7%20%2B%20y%20%20%3D%20%2040)
=> ![y = 13.3](https://tex.z-dn.net/?f=y%20%3D%2013.3)
Now substituting y and
into second equation
![0.75(26.7) + (1.5* 13.3) = 40](https://tex.z-dn.net/?f=0.75%2826.7%29%20%2B%20%20%281.5%2A%2013.3%29%20%3D%20%2040)
=> ![40 = 40](https://tex.z-dn.net/?f=40%20%3D%2040)
So ![y = 13.3](https://tex.z-dn.net/?f=y%20%3D%2013.3)
Answer:
The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction
Explanation:
In order to calculate the magnitude and direction of the magnetic field, you take into account the following equation for the magnetic force on the proton:
(1)
v: speed of the proton = 9.9*10^5 m/s
q: charge of the proton = 1.6*10^-19C
B: magnetic field = ?
FB: magnetic force on the proton = 1.6*10^-13N
When the proton travels in the positive y direction (^j), you have that the proton experiences a force in the positive z direction (+^k). To obtain this direction of the magnetic force on the proton, it is necessary that the magnetic field points in the negative x direction, in fact, you have:
^j X (-^i) = -(-^k)=^k
To obtain the magnitude of the magnetic field you use:
![F_B=qvBsin90\°=qvB\\\\B=\frac{F_B}{qv}=\frac{1.6*10^{-13}N}{(1.6*10^{-19}C)(9.9*10^5m/s)}\\\\B=1.01T](https://tex.z-dn.net/?f=F_B%3DqvBsin90%5C%C2%B0%3DqvB%5C%5C%5C%5CB%3D%5Cfrac%7BF_B%7D%7Bqv%7D%3D%5Cfrac%7B1.6%2A10%5E%7B-13%7DN%7D%7B%281.6%2A10%5E%7B-19%7DC%29%289.9%2A10%5E5m%2Fs%29%7D%5C%5C%5C%5CB%3D1.01T)
The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction