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3 years ago

When a acid and alkali react it is known as?

Chemistry

2 answers:

vfiekz [6]3 years ago

4 0

I think it's a combustion

I am Lyosha [343]3 years ago

3 0

When an acid and an alkali react, a reaction known as "neutralisation reaction" occurs. The result of this reaction is salt and water. Different types of salts are obtained based on which acids and alkalis are used. The common salts include Sodium Chloride.

I think, we can call it "neutralisation reaction" since a reaction occurs.

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P + O2 → P4O10 balance the equation

poizon [28]

4P + 502 -> P4O10 this is the answer

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2 years ago

In Keynes's liquidity preference framework, as the expected return on bonds increases (holding everything else unchanged), the e

Julli [10]

Answer:

the correct words to fill up the blank spaces are falls and money

Explanation:

.1. the expected return on money falls

.2. causing the demand for money to fall.

3 0

3 years ago

Identify the conjugate acid/base pairs in each of the following equations:

Valentin [98]

Answer:

(a) Pair 1: H₂S and HS⁻

Pair 2: NH₃ and NH₄⁺

(b) Pair 1: HSO₄⁻ and SO₄⁻

Pair 2: NH₃ and NH₄⁺

Pair 2: CH₃O⁻ and CH₃OH

(d) Pair 1: HNO₃ and NO₃⁻

Pair 2: H₃O⁺

Explanation:

When an acid loses its proton (H⁺), a conjugate base is produced.

When a base accepts a proton (H⁺), it forms a conjugate acid.

(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.

NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺

(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.

The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.

CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.

(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.

H₂O gains a proton to form the conjugate acid H₃O⁺.

6 0

3 years ago

What part of the water cycle involves the leaves of plants

zvonat [6]

Answer: The answer to this question is transpiration.

Explanation: I know this answer because i looked it up in a book. The other explanation is I study about this a lot.

5 0

2 years ago

Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co

amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as $p_{d}$ and the proportion of air that is by-passed as $p_{bp}$ , being $p_{d}+p_{bp}=1$ .

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

$0.004 = 0.016*p_{bp}+ 0.002*p_{d}$

Replacing the first equation in the second one we have

$0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143$

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

$100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW$

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

7 0

3 years ago

When a acid and alkali react it is known as?​

When a acid and alkali react it is known as?