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jonny [76]
3 years ago
13

HNO3 + KOH → ____ + _____

Chemistry
1 answer:
natita [175]3 years ago
7 0

Answer:

HNO3 + KOH → _KNO3___ + __H2O___

Explanation:

It's balanced

hope it helps

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How many grams of gas must be released from a 32.0 L sample of CO2(g) at STP to reduce the volume to 16.6 L at STP?
Hoochie [10]

Answer:

30.3 g

Explanation:

At STP, 1 mol of any gas will occupy 22.4 L.

With the information above in mind, we <u>calculate how many moles are there in 32.0 L</u>:

  • 32.0 L ÷ 22.4 L/mol = 1.43 mol

Then we <u>calculate how many moles would there be in 16.6 L</u>:

  • 16.6 L ÷ 22.4 L/mol = 0.741 mol

The <u>difference in moles is</u>:

  • 1.43 mol - 0.741 mol = 0.689 mol

Finally we <u>convert 0.689 moles of CO₂ into grams</u>, using its <em>molar mass</em>:

  • 0.689 mol * 44 g/mol = 30.3 g
6 0
3 years ago
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fiasKO [112]

Answer:land

Explanation:

6 0
3 years ago
How many moles are in 20 grams of O₂ gas?
Dima020 [189]
20 g O2 x 1 mol O2/32 g O = 0.625 mol O2
4 0
3 years ago
How much energy does it take to boil 500.g of water at its boiling point?
Tatiana [17]

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7 0
3 years ago
For the reaction
s2008m [1.1K]

Answer:

0.558mole of SO₃

Explanation:

Given parameters:

Molar mass of SO₃ = 80.0632g/mol

Mass of S = 17.9g

Molar mass of S = 32.065g/mol

Number of moles of O₂ = 0.157mole

Molar mass of O₂ = 31.9988g/mol

Unknown:

Maximum amount of SO₃

Solution

  We need to write the proper reaction equation.

           2S + 3O₂ → 2SO₃

We should bear in mind that the extent of this reaction relies on the reactant that is in short supply i.e limiting reagent. Here the limiting reagent is the Sulfur, S. The oxygen gas would be in excess since it is readily availbale.

So we simply compare the molar relationship between sulfur and product formed to solve the problem:

First, find the number of moles of Sulfur, S:

   Number of moles of S = \frac{mass }{molar mass}

   Number of moles of S =  \frac{17.9 }{32.065} = 0.558mole

Now to find the maximum amount of SO₃ formed, compare the moles of reactant to the product:

       2 mole of Sulfur produced 2 mole of SO₃

   Therefore; 0.558mole of sulfur will produce 0.558mole of SO₃

5 0
3 years ago
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