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lapo4ka [179]
3 years ago
10

22) A driver traveling at 80 km/h brakes her 2000 kg truck to stop for a red light. How much internal energy is produced

Physics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

E=4.9\times 10^5\ J

Explanation:

Given that,

The speed of a driver, v = 80 km/h = 22.22 m/s

The mass of the truck, m = 2000 kg

We need to find how much internal energy is produced. The internal energy produced by a truck is its kinetic energy and it is given by :

E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\cdot22.22^{2}\cdot2000\\\\E=493728.4\ J

or

E=4.9\times 10^5\ J

So, 4.9\times 10^5\ J of internal energy is produced.

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The upper arm muscle is _______________ to the skin.
Nikolay [14]

Answer:

The pectoralis major, latissimus dorsi, deltoid, and rotator cuff muscles connect to the humerus and move the arm. The muscles that move the forearm are located along the humerus, which include the triceps brachii, biceps brachii, brachialis, and brachioradialis.

5 0
3 years ago
Read 2 more answers
A 50 kg laboratory worker is exposed to 30 mJ of neutron radiation with an RBE of 10. Part A What is the dose in mSv
lys-0071 [83]

Answer:

The dose is 6 mSV

Explanation:

The absorbed dose (in gray - Gy) is the amount of energy that ionizing radiation deposits per unit mass of tissue. That is,

Absorbed dose = Energy deposited / Mass

while Dose equivalent (DE) (in Seivert -Sv) is given by

DE = Absorbed dose × RBE (Relative biological effectiveness)

First, we will determine the Absorbed dose

From the question, Energy deposited = 30mJ and Mass = 50kg

From,

Absorbed dose = Energy deposited / Mass

Absorbed dose = 30mJ/50kg

Absorbed dose = 0.6 mGy

Now, for the Dose equivalent (DE)

DE = Absorbed dose × RBE

From the question, RBE = 10

Hence,

DE = 0.6mGy × 10

DE = 6 mSv

5 0
3 years ago
A circuit contains an EMF source, a resistor R, a capacitor C, and an open switch in series. The capacitor initially carries zer
Flura [38]

Answer:

t = 1.098*RC

Explanation:

In order to calculate the time that the capacitor takes to reach 2/3 of its maximum charge, you use the following formula for the charge of the capacitor:

Q=Q_{max}[1-e^{-\frac{t}{RC}}]         (1)

Qmax: maximum charge capacity of the capacitor

t: time

R: resistor of the circuit

C: capacitance of the circuit

When the capacitor has 2/3 of its maximum charge, you have that

Q=(2/3)Qmax    

You replace the previous expression for Q in the equation (1), and use properties of logarithms to solve for t:

Q=\frac{2}{3}Q_{max}=Q_{max}[1-e^{-\frac{t}{RC}}]\\\\\frac{2}{3}=1-e^{-\frac{t}{RC}}\\\\e^{-\frac{t}{RC}}=\frac{1}{3}\\\\-\frac{t}{RC}=ln(\frac{1}{3})\\\\t=-RCln(\frac{1}{3})=1.098RC

The charge in the capacitor reaches 2/3 of its maximum charge in a time equal to 1.098RC

6 0
4 years ago
assume that in an unpolished floor a lady us pushing a 40 kg box to the left with an applied force of 192 N. find the sum of for
son4ous [18]
The sum of force is 7,680...............
8 0
3 years ago
The ____ method of assessing intake is time consuming, and the results may not be accurate if subjects modify their eating habit
Gelneren [198K]

Answer:

Food record

Explanation:

A food record method is an assessment, study or act of collecting data related to food.

Although Food record method is time consuming and may not be accurate if subjects modify their eating habits during the time of the study the data collected here are of great importance. Some of the importance are;

(1). It helps in the registration of foods.

(2). The data can be used to describe a population's intake.

(3). The data can be used as a reference parameter in validation studies.

(4). The data can also be used with the Food Frequency Questionnaire.

It other disadvantage apart from its time consuming and error that might occur during the process of conducting the research is that it might be burdensome to the respondents.

6 0
3 years ago
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