Which phrases accurately describe acids? Check all that apply.
2 answers:
Answer: Option 1, 4 and 5 describe acids accurately.
Explanation:
Option 1: Acids have a sour taste because of the concentration of ion.
Option 2: They are corrosive in nature, that is they are not at all gentle with the skin and fabric as some acids intend to burn skin such as is a strong acid which can burn skin as well as fabric.
Option 3: Acids need electrons to release ions and non-metals do not donate electrons hence, there is no reaction between a non-metal and an acid.
Option 4: All acids do contain hydrogen. They dissociate in the presence of water to produce ions.
Option 5: Acids do conduct electricity that is they carry electrical charges. This was explained by Arrhenius. He said that the acids dissociate into ions, when it is dissolved in water. These ions hence acts as charge carriers in water.
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Answer:
See explanation and images attached
Explanation:
There are two compounds that could have molecular formula of C2H6O, they are ethanol and methoxy methane (trivial name: methyl ether). The structures of the two compounds are shown in the image attached as obtained from quora.
The boiling point of methoxymethane is -24.8°C while that of ethanol is about 78.5°C. The reason for the high boiling point of ethanol is the presence of intermolecular hydrogen bonding leading to a stronger intermolecular interaction compared to methoxymethane molecules held together only by very weak dispersion forces.
Answer:
Structure in attachment.
Explanation:
The oxymercuration-demercuration of an asymmetric alkene usually produces the Markovnikov orientation of an addition. The electrophile ⁺Hg(OAc), formed by the electrophile attack of the mercury ion, remains attached to least substituted group at the end of the double bond. This electrophile has a considerable amount of positive charge on its two carbon atoms, but there is more positive charge on the more substituted carbon atom, where it is more stable. The water attack occurs on this more electrophilic carbon, and the Markovnikov orientation occurs.
In hydroboration, borane adds to the double bond in one step. Boron is added to the less hindered and less substituted carbon, and hydrogen is added to the more substituted carbon. The electrophilic boron atom adds to the less substituted end of the double bond, positioning the positive charge (and the hydrogen atom) at the more substituted end. The result is a product with the anti-Markovnikov orientation.
