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2 years ago

How does scarcity impact society

Chemistry

2 answers:

Alisiya [41]2 years ago

8 0

Answer:

Hii There!

Here’s ur answer!

Scarcity affects society in every way. First and foremost, scarcity affects the way that individuals make choices. Time and money are two examples of...

Explanation:

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g100num [7]2 years ago

3 0

Answer:

a market/society is dictated by supply and demand and scarify affects the supply of a product because if something is more scarce/rare then usually there is a higher demand and a higher price. This impacts society because it affects the price of things and how much people are willing to give for it

Explanation:

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The chemical equation for a reaction between K2Cr2O7 and HCl is shown. K2Cr2O7 + 14HCl → 2CrCl3 + 2KCl + 3Cl2 + 7H2O

guapka [62]

Answer: The correct answer is Option b.

Explanation:

Oxidizing agent is defined as the chemical reagent which helps the other chemical compound to get oxidized and itself gets reduced. The oxidation state for these species gets reduced because they are undergoing reduction reaction.

For the given chemical equation:

$K_2Cr_2O_7+14HCl\rightarrow 2CrCl_3+2KCl+3Cl_2+7H_2O$

Oxidation state of Chromium is getting reduced from +6 to +3 and oxidation state of chlorine getting increased from -1 to 0.

Hence, $K_2Cr_2O_7$ acts like and oxidizing agent because it is itself getting reduced to $CrCl_3$

Therefore, the correct answer is Option b.

4 0

3 years ago

A 6 kg rock is sitting at the edge of a 100 m tall cliff. What is the potential energy of the rock with respect to the ground?

Hatshy [7]

Potential energy can be calculated by the formula Pe=mgh. Plug in your values:

Pe=mgh
Pe=(6 kg)(9.8m/s^2)(100 m)
Pe=5880 kg x m^2/s^2, or 5880 Joules

5 0

3 years ago

What are the elements in group 3-12 called

Wittaler [7]

Answer:

Transition Metals

Explanation:

The elements in groups 3-12 are called Transition Metals. These groups contain metals that usually form multiple cations. All other groups on the table (1, 2, 13-18) are called Main Group Elements.

5 0

3 years ago

A 33.0 mL sample of 1.15 M KBr and a 59.0 mL sample of 0.660 M KBr are mixed. The solution is then heated to evaporate water unt

Oksi-84 [34.3K]

Answer:

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

Explanation:

Step 1: Data given

Sample 1: The 1.15 M sample has a volume of 33.O mL

Sample 2: The 0.660 M sample has a volume of 59.0 mL

Molar mass of KBr = 119 g/mol

Molar mass of AgNO3 = 169.87 g/mol

Step 2: Calculate number of moles for both samples

Number of moles = Molarity * Volume

Sample 1: 1.15 M * 33 *10^-3 L = 0.03795 moles

Sample 2: 0.660 M *59*10^-3 L = 0.03894 moles

Total mol KBr = 0.03795 + 0.03894 = 0.07689 moles

Step 3: Calculate total mass

mass = Number of moles * Molar mass

mass = 0.07689 moles * 119 g/moles = 9.15 grams ( in 55mL)

Step 4: Calculate moles of AgBr

AgNO3 reacts with KBr

KBr(aq) + AgNO3(aq) → AgBr(s) + KNO3(aq)

1 mole of KBr consumed, needs 1 mole of AgNO3 to produce 1 mole of AgBr and 1 mole of KNO3

So 0.07689 moles of KBr wll need 0.07689 moles of AgNO3

Step 5: Calculate mass of silver nitrate

mass of AgNO3 = Moles of AgNO3 * Molar mass of AgNO3

mass of AgNO3 = 0.07689 moles * 169.87 g/mol = 13.06 grams

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

8 0

3 years ago

Why are alkali metals so reactive?

Savatey [412]

Answer:

Alkali metals are among the most reactive metals. This is due in part to their larger atomic radii and low ionization energies. They tend to donate their electrons in reactions and have an oxidation state of +1. ... All these characteristics can be attributed to these elements' large atomic radii and weak metallic bonding.

Explanation:

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8 0

2 years ago