Fractional distillation
Explanation:
The best way to separate the mixtures out is through the process of fractional distillation.
In fractional distillation, liquid - liquid mixtures are separated based on the differences in boiling point of their components. Let us examine the boiling points of the component of the mixtures:
Ethanol 78⁰C
Glycerol 290⁰C
Ethylene glycol 197.6⁰C
Methanol 64.7⁰C
Water 100⁰C
We see that the liquids in the mixture have different boiling points. In this process, the mixture is heated in a distillation column. When the boiling point of any component is reached, it will rise up in the column and can be channeled to a condenser where it is cooled and collected.
The liquid with the least boiling point is first separated with the one with the highest boiling is recovered last:
Order of recovery;
Methanol 64.7⁰C
Ethanol 78⁰C
Water 100⁰C
Ethylene glycol 197.6⁰C
Glycerol 290⁰C
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This is the answer to question 19. If it’s not clear, send me a message.
The value of Keq = 110
Let's know how to get it :
According to the equilibrium reaction equation :
I2(g) + Br2(g) → 2IBr(g)
now we need to get the value of Keq
when the Keq expression is:
Keq = [IBr]^2/ [I] [Br]
when we have [IBr] at equilibrium = 0.84 so we need to get [I] &[Br] at equilibrium .
when [Br2] = [I2] = 0.5 - 0.84 / 2
= 0.08 M
so, by substitution
∴ Keq = (0.84)^2/(0.08)^2
= 110
Mass of iron(ll) oxide= 616.608 g
<h3>Further explanation</h3>
Given
Reaction
2Fe+O2 -->2FeO
479.6 grams of iron
Required
mass of iron(ll) oxide
Solution
mol of iron :
= mass : Ar Fe
= 479.6 g : 56 g/mol
= 8.564
From the equation, mol FeO :
= 2/2 x mol Fe
= 2/2 x 8.564
= 8.564 moles
Mass of iron(ll) oxide :
= mol x MW
= 8.564 x 72 g/mol
= 616.608 g
Answer:
water
Explanation:
because the others are in compounds and can not be considered as products lonely.
