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Sveta_85 [38]
3 years ago
6

Respond to the following based on your reading (write your answers using 1–2 paragraphs). 1. Describe the universal gravitationa

l law. 2. Evaluate the techniques and models used by Ptolemy and Copernicus to explain the setup of the universe. 3. A child picks up a tennis ball tied to the end of a rope. He swings the rope around, over his head, in a circle. Once the ball is spinning, he lets go of the string and the ball goes flying. Explain which of the following images correctly shows which way the ball will fly and why. Two images of figures throwing a ball and their potential trajectory 1. Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. 2. Ptolemy believed in the theory that the earth was the center of the universe (geocentric) and it is not moving in the center while Copernicus later proposed otherwise, in his heliocentric theory he believed that the sun was the center of the universe but it was not moving. Both theories were influenced by their observation of how the light shade from the sun changes during the day, and also through observation of other celestial bodies whose light intensity changes which made them arrived to the conclusion that they are not equidistant nor stationary with respect to earth. 3. Plan A Explanation: Acceleration in a circle is toward the center of the circle, while velocity is always a straight line that's tangent to the circle. When the boy let's go of the rope the Acceleration toward the center of the circle disappears. The v ball then follows the straight path, tangent to the circle.
Physics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:

Explanation:

1. Discovered by Sir Isaac Newton, this law states that every object in the universe that has mass attracts every other object in the universe that has mass. The force is proportional to the product of the two masses and inversely proportional to the square of the distance between their centers. When applying this to a situation with two objects, the object with the smaller mass will do most of the moving because the other object has too much inertia to move any noticeable amount.

2. Without advanced technology like we have today, Ptolemy and Copernicus tried to best explain the model of the universe through observation. Ptolemy’s model came first and placed a stationary earth at the center of the model. Everything else moved in respect to earth. This was widely accepted since it seemed like earth wasn’t moving. Ptolemy stated that the planetary bodies moved around earth in circular paths. However, this wasn’t always witnessed through observation. He adjusted his model to state that some planets must be moving in secondary orbits.

Copernicus put a rotating earth in a sun-centered model. The rotation of earth was able to account for the rising and setting of stars. The orbital motion of the earth and moon also accounted for the motion of the sun and moon with respect to the stars. This was easier to understand but encountered scrutiny due to its differences from religious teachings.

One big difference between the approaches in the two is that Copernicus didn’t try to adjust his model to match what was going on; he used observations to develop the model. In addition, one common trend in science is that the simplest explanation is usually most accurate or closer to accurate. Copernicus’ model was more straightforward; Ptolemy’s was more complex.

3. Acceleration in a circle is toward the center of the circle, while velocity is always a straight line that's tangent to the circle. Thus, when the boy lets go of the rope, the centripetal force (acceleration) toward the center of the circle disappears. The ball then follows the straight path, tangent to the circle, and follows Path A.

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A constant 20 N force is applied to a 7 kg box to push it along the ground. How
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Answer:

40 joules

Explanation:

Work Done=Force*Distance

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3 years ago
Water is boiled at 1 atm pressure in a 25-cm-internal- diameter stainless steel pan on an electric range. if it is observed that
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<span>3933 watts At 100 C (boiling point of water), it's density is 0.9584 g/cm^3. The volume of water lost is pi * 12.5^2 * 10 = 4908.738521 cm^3 The mass of water boiled off is 4908.738521 * 0.9584 = 4704.534999 grams. Rounding to 4 significant figures gives me 4705 grams of water. The heat of vaporization for water is 2257 J/g. So the total energy applied is 2257 J/g * 4705 g = 10619185 J Now we need to divide that by how many seconds we've spent boiling water. That would be 45 * 60 = 2700 seconds. Finally, the rate of heat transfer in Joules per second will be the total number of joules divided by the total number of seconds. So 10619185 J / 2700 s = 3933 J/s = 3933 (kg m^2/s^2)/s = 3933 (kg m^2/s^3) = 3933 watts</span>
3 0
3 years ago
Use the Bohr model to address this question. When a hydrogen atom makes a transition from the 5 th energy level to the 2nd, coun
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Answer:

A. 2.82 eV

B. 439nm

C. 59.5 angstroms

Explanation:

A. To calculate the energy of the photon emitted you use the following formula:

E_{n1,n2}=-13.4(\frac{1}{n_2^2}-\frac{1}{n_1^2})     (1)

n1: final state = 5

n2: initial state = 2

Where the energy is electron volts. You replace the values of n1 and n2 in the equation (1):

E_{5,2}=-13.6(\frac{1}{5^2}-\frac{1}{2^2})=2.82eV

B. The energy of the emitted photon is given by the following formula:

E=h\frac{c}{\lambda}   (2)

h: Planck's constant = 6.62*10^{-34} kgm^2/s

c: speed of light = 3*10^8 m/s

λ: wavelength of the photon

You first convert the energy from eV to J:

2.82eV*\frac{1J}{6.242*10^{18}eV}=4.517*10^{-19}J

Next, you use the equation (2) and solve for λ:

\lambda=\frac{hc}{E}=\frac{(6.62*10^{-34} kg m^2/s)(3*10^8m/s)}{4.517*10^{-19}J}=4.39*10^{-7}m=439*10^{-9}m=439nm

C. The radius of the orbit is given by:

r_n=n^2a_o   (3)

where ao is the Bohr's radius = 2.380 Angstroms

You use the equation (3) with n=5:

r_5=5^2(2.380)=59.5

hence, the radius of the atom in its 5-th state is 59.5 anstrongs

8 0
3 years ago
Which pair of equations can describe the path of a particle moving with an acceleration that is perpendicular to the velocity of
antoniya [11.8K]

Answer:

The question clearly describes the circular motion.

The circular motion equation is

a_{radial} = \frac{v^2}{r}

The path of the particle is circular.

Explanation:

In circular motion, the radial acceleration is always towards the center and constant in magnitude. Furthermore, the velocity of the circular motion is always tangential to the circle, that is it is always perpendicular to the radius, hence the acceleration.

6 0
2 years ago
You are holding a shopping basket at the grocery store with two 0.55-kg cartons of cereal at the left end of the basket. the bas
stepan [7]
Refer to the diagram shown below.

The basket is represented by a weightless rigid beam of length 0.78 m.
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The mass at x=0 is 2*0.55 = 1.1 kg.
The weight acting at x = 0 is W₁ = 1.1*9.8 = 10.78 N

The mass near the right end is 1.8 kg.
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The fulcrum is in the middle of the basket, therefore its location is
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For equilibrium, the sum of moments about the fulcrum is zero.
Therefore
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4.2042 - 17.64x + 6.8796 = 0
-17.64x = -11.0838
x = 0.6283 m

Answer:  0.63 m from the left end.

5 0
2 years ago
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