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sergij07 [2.7K]
3 years ago
13

What is the law of motion​

Physics
1 answer:
777dan777 [17]3 years ago
5 0

Answer:

A body at rest remains at rest and a body in motion remains in uniform motion in a straight line unless acted upon by an external force is law of motion.

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Technician A says the names of the components inside an automatic transmission are based on their function; namely what gear are
topjm [15]

Answer:

Both A and B are correct

Explanation:

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3 years ago
Arrange the values according to magnitude
Talja [164]

Answer:

59000

1.8\times 10^5

4.3\times 10^{-2}

9.0\times 10^{-6}

8.4\times 10^{-6}

Explanation:

The given numbers are

1.8\times 10^5=18000

4.3\times 10^{-2}=0.043

8.4\times 10^{-6}=0.0000084


9.0\times 10^{-6}=0.000009

59000

The arrangement of the numbers from largest to smallest is

59000

1.8\times 10^5

4.3\times 10^{-2}

9.0\times 10^{-6}

8.4\times 10^{-6}.

7 0
3 years ago
Approximately what applied force is needed to keep the box moving with a constant velocity that is twice as fast as before? Expl
professor190 [17]

Complete question:

A force F is applied to the block as shown (check attached image). With an applied force of 1.5 N, the block moves with a constant velocity.

Approximately what applied force is needed to keep the box moving with a constant velocity that is twice as fast as before? Explain

Answer:

The applied force that is needed to keep the box moving with a constant velocity that is twice as fast as before, is 3 N

Force is directly proportional to velocity, to keep the box moving at the double of initial constant velocity, we must also double the value of the initially applied force.

Explanation:

Given;

magnitude of applied force, F = 1.5 N

Apply Newton's second law of motion;

F = ma

F = m(\frac{v}{t} )\\\\F = \frac{m}{t} v\\\\Let \ \frac{m}{t} \ be \ constant = k\\F = kv\\\\k = \frac{F}{v} \\\\\frac{F_1}{v_1} = \frac{F_2}{v_2}

The applied force needed to keep the box moving with a constant velocity that is twice as fast as before;

\frac{F_1}{v_1} = \frac{F_2}{v_2} \\\\(v_2 = 2v_1, \ and \ F_1 = 1.5N)\\\\\frac{1.5}{v_1} = \frac{F_2}{2v_1} \\\\1.5 = \frac{F_2}{2}\\\\F_2 = 2*1.5\\\\F_2 = 3 N

Therefore, the applied force that is needed to keep the box moving with a constant velocity that is twice as fast as before, is 3 N

Force is directly proportional to velocity, to keep the box moving at the double of initial constant velocity, we must also double the value of the applied force.

3 0
4 years ago
The diagram above shows four light bulbs wired in a circuit. What would happen if bulb 3 burned out
andre [41]
The lights will no longer work because the circuit will be cut
6 0
3 years ago
When velocity is graphed with respect to time, what does the area under
Juliette [100K]

Answer:

the answer is D

Explanation:

Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.

4 0
3 years ago
Read 2 more answers
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