Answer:
3.840 atm
Explanation:
We use Boyle's law, which relates the pressure (P) and the volume (V) of a gas at a constant temperature. The change from initial P and V (P₁ and V₁) to final P and V (P₂ and V₂) is expressed as:
P₁V₁ = P₂V₂
We have the following data:
P₁= 0.960 atm
V₁= 200.0 mL
V₂ = 50.0 mL
Thus, we introduce the data in the equation and calculate the final pressure P₂:
P₂ = P₁V₁/V₂= (0.960 atm x 200.0 mL)/50.0 mL = 3.840 atm
Therefore, a pressure of 3.840 atm is needed to reduce the volume of the gas from 200.0 mL to 50.0 mL.
Answer:
<h3>The answer is 82.86 cm³</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass of wood = 44 g
density = 0.531 g/cm³
It's volume is
We have the final answer as
<h3>82.86 cm³</h3>
Hope this helps you
Answer:
T₂ = 218.75 K
Explanation:
Given data:
Initial volume = 20 L
Initial pressure = 16 atm
Initial temperature = 500 K
Final temperature = ?
Final volume = 35 L
Final pressure = 4 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
by putting values,
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁/ P₁V₁
T₂ = 4 atm × 35 L × 500 K / 16 atm × 20 L
T₂ = 70000 atm .L. K / 320 atm.L
T₂ = 218.75 K
Answer:
B. High levels of nitrogen and phosphorus from agricultural runoff, sewage, and industrial pollution were flowing into the bay.
Explanation:
I just did this question! <3
Before an article is published in a scientific journal or in any "peer-reviewed" journal the article is reviewed thoroughly by scholars from the journal as well as peers or scholars of the articles author from the same field. This process occurs to provide credibility to the ideas being published and so that readers and other scholars can rely on the validity of the material being published.
