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Grace [21]
3 years ago
10

Radio waves travelling at 3x108 m/s have a frequency of 1.017x108 Hz. Its wavelength is m rounded to the nearest tenth.

Physics
1 answer:
jonny [76]3 years ago
8 0

Answer: 3 metres

Explanation:

The wavelength of a wave is the distance covered by the wave after one complete cycle. It is measured in metres, and represented by the symbol λ.

Recall that Velocity (V) = Frequency F x wavelength λ

In this case, wavelength (λ)= ?

Frequency of radio wave = 1.017x10^8 Hz

Velocity of radio waves = 3x10^8 m/s

Apply V = F λ

3x10^8 m/s = 1.017x10^8 Hz x λ

Make λ the subject formula

λ = (3x10^8 m/s / 1.017x10^8 Hz)

λ = 2.95 metres (To the nearest tenth, it becomes 3 metres)

Thus, the wavelength of the radio waves is 3metres

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Is more of north america north or south of the tropic of cancer
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Read 2 more answers
A mass is oscillating with amplitude A at the end of a spring.
Dmitry_Shevchenko [17]

A) x=\pm \frac{A}{2\sqrt{2}}

The total energy of the system is equal to the maximum elastic potential energy, that is achieved when the displacement is equal to the amplitude (x=A):

E=\frac{1}{2}kA^2 (1)

where k is the spring constant.

The total energy, which is conserved, at any other point of the motion is the sum of elastic potential energy and kinetic energy:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 (2)

where x is the displacement, m the mass, and v the speed.

We want to know the displacement x at which the elastic potential energy is 1/3 of the kinetic energy:

U=\frac{1}{3}K

Using (2) we can rewrite this as

U=\frac{1}{3}(E-U)=\frac{1}{3}E-\frac{1}{3}U\\U=\frac{E}{4}

And using (1), we find

U=\frac{E}{4}=\frac{\frac{1}{2}kA^2}{4}=\frac{1}{8}kA^2

Substituting U=\frac{1}{2}kx^2 into the last equation, we find the value of x:

\frac{1}{2}kx^2=\frac{1}{8}kA^2\\x=\pm \frac{A}{2\sqrt{2}}

B) x=\pm \frac{3}{\sqrt{10}}A

In this case, the kinetic energy is 1/10 of the total energy:

K=\frac{1}{10}E

Since we have

K=E-U

we can write

E-U=\frac{1}{10}E\\U=\frac{9}{10}E

And so we find:

\frac{1}{2}kx^2 = \frac{9}{10}(\frac{1}{2}kA^2)=\frac{9}{20}kA^2\\x^2 = \frac{9}{10}A^2\\x=\pm \frac{3}{\sqrt{10}}A

3 0
3 years ago
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