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notka56 [123]
3 years ago
13

(1.24) Consumer Reports is doing an article comparing refrigerators in their next issue. Some of the characteristics to be inclu

ded in the report are the brand name and model; whether it has a top, bottom, or side-by-side freezer; the estimated energy consumption per year (kilowatts); whether or not it is Energy Star compliant; the width, depth, and height in inches; and both the freezer and refrigerator net capacity in cubic feet. The "Height" is categorical variable, quantitative variable, or individuals
Engineering
1 answer:
kondaur [170]3 years ago
8 0

Answer:

“height is a quantitative variable ”

Explanation:

According to the question asked, answer is “height is a quantitative variable ”

Height is a quantitative variable because it is related to the measurement and in measurement, when we measure something we deal with number (numerical data)

Numerical data is a type of quantitative data that is why we say “height is a quantitative variable”  

There are some other possible questions in the given paragraph which I would like to mention here,  are as following:

Which are the categorical variables in the given report?

<u>Answer: </u>Energy star complaints

Top, Bottom or side-by-side freezer

Which are the quantitative variables in the given report?

<u>Answer:</u> Estimated Energy Consumption in kilowatts

Width, depth, and height in inches

Capacity in Cubic Feet  

What are the individuals in the report?

<u>Answer: </u>The brand name and model  

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i think it is D tell me if its wrong

Explanation:

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A round bar of chromium steel, (ρ= 7833 kg/m, k =48.9 W/m-K, c =0.115 KJ/kg-K, α=3.91 ×10^-6 m^2/s) emerges from a heat treatmen
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Answer:

Q = 424523.22 kw

Explanation:

\rho =7833 kg/m

k = 48.9 W/m - K

c = 0.115 KJ/kg- K

\alpha = 3.91*10^{-6} m^2/s

T_s = 285 degree celcius

T_∞ = 35 degree celcius

velocity of air stream = 15 m/s

D = 40 cm

L = 200 cm

mass flow rate\dot m = \rho AV = 7833 *\frac{\pi}{4} 0.4^2*15

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A_s = \pi DL = \pi 0.4*2 = 2.513 m^2

Q = \dot m C \Delta T = h A_s \Delta T

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solving for h

h = \frac{14764.85*0.115*(285-35)}{2.513*(285-35)}

h = 675.6 kw/m^2K

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25 In differential aeration corrosion, rich oxygenated parts are
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A cooling system load is 96,000 BTUh sensible. How much chilled air is required to satisfy the load if the system is designed fo
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For 20^{\circ} - 5.556 lb/s

For 15^{\circ} - 7.4047 lb/s

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As per the question:

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Specific heat of air, C_{p} = 0.24 btu/lb ^{\circ}F

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\dot{m}C_{p}\Delta T = 96000

\dot{m} = \frac{96000}{C_{p}\Delta T} = \frac{96000}{0.24\times 20} = 20000 lb/h = \frac{20000}{3600} = 5.556 lb/s

Now, for 15^{\circ}:

\dot{m}C_{p}\Delta T = 96000

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